Need help on rotational dynamics problem quick please

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SUMMARY

The discussion focuses on solving a rotational dynamics problem involving an inverted "A" structure suspended by two vertical ropes. Each leg of the "A" has a length of 2L and a weight of 120.0N, with the angle at the top being 60 degrees. The key concept is that the system is in static equilibrium, meaning the net force and torque are zero. Participants emphasize the importance of applying the formula W=Fcos(d) to determine the forces acting on each leg, while also questioning the provided dimensions for clarity.

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hi i need help understanding what to do with the information that was given in the problem if u could point mein the right direction i would greatly appreciate it. thank you

An invered "A" is suspended from the ceiling by 2 vertical ropes. Each leg of the "A" has a length of 2L and a weight of 120.0N. The horizontal crossbar has a negligable weight. Find the force that the crossbar applies to each leg.
Known:
W=120.0N per leg
l of legs= 2L
angle at top of "A" = 60Degrees
l of crossbar=L
 
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I think the key idea here is that the system is in static equilibrium. That means that the net force and torque are zero. Can you take it from there?
 
Parth Dave is right. The system is at rest so the net force is 0. If that is not the case read below.

the formula is W=Fcosd

but what doesn't make sense is that you don't have the displacement. Are you sure it says 2L not 2m.
 
Last edited:

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