Angle of intersection between two parametric curvesby ElijahRockers Tags: angle, intersection, parametric, vector 

#1
Jan2512, 08:38 PM

P: 195

1. The problem statement, all variables and given/known data
This is a problem involving parametric equations. r_{1}= <t,2t,12+t^{2}> r_{2}= <6s,s4,s^{2}> At what point do the curves intersect? Find the angle of intersection, to the nearest degree. 3. The attempt at a solution I found the point of intersection, (2,0,16). This is when t=2 and s=4. I found the tangent vectors. d/dt(r1) = <1,1,2t> d/ds(r2) = <1,1,2s> I used r_{1}[itex]\cdot[/itex]r_{2} = r1r2cos[itex]\theta[/itex], using the tangent vectors at t=2 and s=4, and solved for theta.. I came up with 23°, but the system tells me I'm wrong. What happened? EDIT:: Okay.... it seems like I was coming up with a different answer every time. Got it on my last try though. Gotta be more careful... for anyone wondering, the correct answer is 29° 


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