| New Reply |
Help Finding Roots of Polynomial |
Share Thread | Thread Tools |
| Jan30-12, 04:07 PM | #1 |
|
|
Help Finding Roots of Polynomial
1. The problem statement, all variables and given/known data
First find all rational zeros of f, then use the depressed equation to find all roots of the equation f(x) = 0. f(x) = x^3 + 5x^2 - 8x + 2 2. Relevant equations 3. The attempt at a solution Possible rational zeros: 2, -2, 1, -1 Synthetic division: 1 | 1 5 -8 2 _____1 6 -2 ============= 1 6 -2 0 Quotient: x^2 + 6x - 2 Factored: (x + 3)^2 - 11 I would think that the answer would just be x = -3 ± √(11) but the answer in the book says: {1, -3 ± √(11)} Where'd the 1 come from? |
| Jan30-12, 04:36 PM | #2 |
|
Recognitions:
|
Remember, you divided by (x-1), so your equation become (x-1)(x^2+6x-2)=0 -> x= 1 in addition to the other roots you found.
|
| Jan30-12, 04:37 PM | #3 |
|
|
Ohhhhhhh! I see now, thank you!
|
| Jan31-12, 12:33 AM | #4 |
|
|
Help Finding Roots of Polynomial
synthetic division, oh lord
if you want a nicer division algorithm try this http://www.youtube.com/watch?v=V-Q6jBYn3Oc or proper polynomial long division ... I really hated synthetic division :p |
| Jan31-12, 03:29 PM | #5 |
|
Recognitions:
|
I believe we've had this discussion before, but there's nothing wrong with synthetic division. It's quick and pretty straightforward, IMO. Of course, if you're trying to divide a polynomial by a quadratic or a higher degree polynomial, then long division is the way to go.
|
| New Reply |
| Tags |
| depressed equation, roots, zeros |
| Thread Tools | |
Similar Threads for: Help Finding Roots of Polynomial
|
||||
| Thread | Forum | Replies | ||
| Roots of a Polynomial | Calculus & Beyond Homework | 0 | ||
| Help! Getting the roots of a polynomial | Calculus & Beyond Homework | 13 | ||
| Polynomial Roots | Precalculus Mathematics Homework | 5 | ||
| polynomial roots | General Math | 1 | ||
| Roots of polynomial | General Math | 12 | ||