Circular Velocity: Speed of Second Hand

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Homework Help Overview

The discussion revolves around calculating the speed of the tip of the second hand of a clock, given the speed of the minute hand. The subject area includes concepts of angular velocity and centripetal acceleration.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants explore the relationship between linear speed and angular velocity, with some attempting to derive the speed of the second hand based on the known speed of the minute hand. Questions arise regarding the application of angular velocity and the interpretation of time measurements related to the second hand.

Discussion Status

Some participants have provided calculations and reasoning regarding the relationship between the speeds of the minute and second hands. There is a mix of understanding, with some expressing confusion about the underlying concepts and the calculations presented. Clarifications about the measurement of time by the second hand have also been discussed.

Contextual Notes

Participants are working under the constraints of a homework assignment, which may limit the information they can use or the methods they can apply. There is also a noted confusion regarding the terminology related to time measurement.

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The speed of the tip of the minute hand on a town clock is 0.00112 m/s.
What is the speed of the tip of the second hand of the same length? Answer in units of m/s.

I don't even know where to start. We've been doing centripetal acceleration but I don't know how this even fits into that?
I was thinking I could somehow set them equal to each other because of the same length that they have - but not sure how to go about that.

If anyone could please help?
 
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I'm assuming what you know what angular velocity is. It is related to speed by

v = ω*r

where r is the radius. The angular velocity is just ΔAngle/ΔTime.

So in this case the radius or length of the minute hand can be calculated as

r = v/ω

this is also the length of the second hand, seeing as their lengths are the same. The minute hand does one revolution every hour, so

ΔAngle = 2*PI
ΔTime = 1 hr = 60*60 s = 3600s

so for the minute hand ω = PI/(1800s) = PI / 1800 s^-1

Let V and Ω be the speed and angular velocity respectively of the second hand

so, r = V/Ω

seeing as their lenghs are equal we have

V/Ω = v/ω
V = v * Ω / ω

seeing as the second hand goes around the clock once every 60 seconds then its angular velocity is PI/30 s^-1.

So, V = 0.00112 m/s * ( PI/30 s^-1 ) / ( PI / 1800 s^-1 )
V = 0.0672 m/s

so the speed of the second hand is 0.0672 m/s.
 
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Haha. I'm still sort of confused about what you did since I'm taking calculus I just now and it's kind of hard to do Calculus based Physics. I'm trying to use the velocity that you gave me for the second hand to find the centripetal acceration of the tip of the second hand? I'm also confused as to how you got Angle/Time from the radius equation.
 
The problem can also be solved by noting the fact that after one revolution of the minute hand around the clock the second hand has made sixty revolutions. Seeing as the second and minute hands are of equal length, then it follows that the speed of the second hand is sixty times faster than the speed of the minute hand! Do the calculations and you'll find this matches the answer above.
 
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I'm a little confused. What does the second hand measure: hours or seconds? If it's seconds the answer is what MathNerd just said, but if it's hours then the speed is 24 times smaller.
 
Believe it or not, Sonty, the second hand measures seconds!

That's why it's CALLED a second hand!

Sorry if this sounds sarcastic, but I've had a hard weekend, someone has to pay, and you stuck your head up!

(What mathnerd is REALLY saying is that, since the second hand makes a complete circle of the clock face every 60 seconds (one minute) while the minute hand does so every 60 minutes (one hour), the second hand is going 60 times as fast: it's speed is

60(0.00112 m/s)= 0.0672 m/s.)
 
Gosh I'm a moron. "second" doesn't always mean 2nd. It seems my weekend was even worse if I couldn't make that connection and writing them next to each other didn't help. Need time away from this damn computer, need real life, need using this english thing more, need...[zz)]
 

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