Kinetic Energy: .00020kg Bullet vs 6.4 x 10^7 kg Ocean Liner

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SUMMARY

The discussion centers on comparing the kinetic energy of a 0.00020 kg bullet traveling at 400 m/s with a 6.4 x 107 kg ocean liner moving at 10 m/s (20 knots). The correct formula for calculating kinetic energy is KE = (1/2)mv2. Using this formula, the ocean liner possesses significantly more kinetic energy than the bullet, illustrating the vast difference in energy between a small projectile and a massive vessel. The conversation suggests that a more balanced comparison would involve a high-powered rifle bullet and a modestly sized ship.

PREREQUISITES
  • Understanding of kinetic energy formula: KE = (1/2)mv2
  • Basic knowledge of mass and velocity units (kg and m/s)
  • Familiarity with the concept of energy comparison
  • Awareness of different scales in physics (e.g., small projectiles vs. large objects)
NEXT STEPS
  • Calculate kinetic energy for various objects using KE = (1/2)mv2
  • Explore the implications of mass and velocity on kinetic energy in real-world scenarios
  • Investigate the differences in kinetic energy between various types of projectiles and vehicles
  • Learn about momentum and its relationship to kinetic energy in physics
USEFUL FOR

Students studying physics, educators teaching energy concepts, and anyone interested in understanding the principles of kinetic energy and its applications in real-world comparisons.

Jimsac
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Not understanding a formula for this problem

Which has more kinectic energy a .00020-kg bullet traveling at 400m/s or a 6.4 10 to 7th power -kg ocean liner traveling at 10m/s (20 knots)?

I know that w=fd=mad=ma(1/2)at2) =1/2m(at)2 +1/2mv2 Is this the right formula?
 
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KE = (1/2)mv^2. Use that to work out the KE for the bullet and the ocean liner, then compare them.
 
Jimsac said:
Not understanding a formula for this problem

Which has more kinectic energy a .00020-kg bullet traveling at 400m/s or a 6.4 10 to 7th power -kg ocean liner traveling at 10m/s (20 knots)?

I know that w=fd=mad=ma(1/2)at2) =1/2m(at)2 +1/2mv2 Is this the right formula?
You can just look at this and see that the ocean liner has much more kinetic energy. It is comparing the energy of .bb gun to the Titanic at full speed! So it isn't a great question. How about a highpowered rifle bullet and a more modest ship moving at a more modest speed :

a 20 gram (.02 kg) bullet at 1000 m/sec, and a 1,500 Tonne ship at 10 cm/sec

AM
 

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