Answer Time & Distance: Thief and Policeman Catch Up

  • Context: High School 
  • Thread starter Thread starter aprao
  • Start date Start date
  • Tags Tags
    Time
Click For Summary
SUMMARY

The problem involves a thief running away from a policeman, initially 100 meters ahead, with the thief's speed at 6 km/h and the policeman's speed at 8 km/h. To determine the time it takes for the policeman to catch the thief, one can set up equations for their positions as functions of time. By equating these position functions, or by calculating the relative velocity of the policeman to the thief, the time can be derived. Both methods yield the same result, reinforcing the mathematical principles involved.

PREREQUISITES
  • Understanding of relative velocity concepts
  • Basic algebra for solving equations
  • Knowledge of speed, distance, and time relationships
  • Familiarity with motion equations in physics
NEXT STEPS
  • Learn how to derive equations of motion for objects in pursuit scenarios
  • Study relative velocity calculations in physics
  • Explore problem-solving techniques for distance and speed problems
  • Practice similar chase problems to reinforce understanding
USEFUL FOR

Students studying physics, educators teaching motion concepts, and anyone interested in solving real-world problems involving speed and distance.

aprao
Messages
4
Reaction score
0
Hai Expert
COuld you please explain to me how to solve the following problems?

Question:
A Thief sees a policeman 100 Metre ahead of him. He Immediately turns back and starts running at 6Kmph. The Policeman chases him at a speed of 8Kmph. After What time does the policeman catch up with the thief ?


Regards
aprao
 
Physics news on Phys.org
Version 1:
1) Let your origin coincide with your police-man's initial position
How can we write the police-man's subsequent position (measured relative, that is, to the origin) as a function of time?
2) Measured from the policeman's initial position, the thief's initial position is 100.
How can we write the thief's subsequent position (measured relative, that is, to the origin) as a function of time?

3) Since at the time when the policeman catches up with the thief, their positions is the same, you may find an equation for the time by equating their position functions at that time.

Version 2:
Compute the relative velocity the policeman has to the thief.
How long would it take a person runnning with this relative velocity to travel 100 meters?

I strongly suggest you work out the time by both versions, and verify that both versions predict the same time.
This will help you enhancing your understanding of the maths&physics involved.
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 55 ·
2
Replies
55
Views
4K
Replies
7
Views
2K
  • · Replies 18 ·
Replies
18
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 21 ·
Replies
21
Views
3K
  • · Replies 14 ·
Replies
14
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 25 ·
Replies
25
Views
2K