|Dec30-04, 08:08 AM||#1|
Another question here .. i attempted it but did not get the correct answer.I will state the question and the steps i took as well.
"A line is drawn through the point (2,3) making an angle of 45 degrees with the positive direction of the x-axis, and it meets the line x=6 at P.Find the distance of P from the origin 0, and the equation of the line through P perpendicular to 0P"
Steps i took:
1)Since i have to find out the distance of 0P i need to have the Y value of the point P. I assumed the X value is 6 (well, they tell you that anyway)
2)To work out the Y value of P i figured that it needs to be worked out by using the equation of the line (2,3). (ie substitue in an X value to the equation of the line (2,3) to get the Y value of point P)
3)However, to work out the equation of the line (2,3), i also have to know the gradient.I worked this out to be 3/2 (Is this right?)
4)Next i found the equation of the line (2,3) and then i substitued in the X value of P (6) .I found the Y-value to be 12. (Is this right?)
5)Now i work out the length of the line (0,0)(6,12) , and it comes out to be: squareroot of 180
Hmm .. im sure all of this is not needed .. i bet (hope/wish) someone will come out with a one line asnwer!
Anyway, any help whatsoever is appreciated
|Dec30-04, 08:32 AM||#2|
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Using the correct equation, the point P is (6,7). So find the distance to the origin.
To find the equation of the line through P that is perpendicular to the line OP, do this: First find the slope of OP; then find the slope of the perpendicular line. Then, using the point P, find the equation for that line.
|Dec30-04, 08:59 AM||#3|
Thanks for your help again.
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