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Magnetic Flux and Induced Voltage Interesing question 
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#1
Feb2812, 04:55 PM

P: 103

1. The problem statement, all variables and given/known data
assuming that friction is negligible and tthat electromagnetic forces are constant, (when they occur) calculate the speed of the cart at point 5w this is part IV of a question, so in the other parts and in the given, i found out that: mass of the cart=0.5kg number of loops=150 hieght of the rampo=0.4m height of the wire=0.1 width=0.2m Resistance: 2.5 ohms Magnetic field=1.2T 2. Relevant equations [itex]\phi[/itex]=BA [itex]\epsilon[/itex]=N[itex]\Delta\phi[/itex]/[itex]\Delta[/itex]t 3. The attempt at a solution The velocity of the cart at the bottom of the ramp is 2.8m/s the Voltage of the cart as it enters the field is 50V the current induced is 20A The force of teh cart as it enters the field is 2.4N, making its acceleration 4.8m/s/s Normal kinematics don't seem to work well, any tip? 


#2
Feb2812, 06:23 PM

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What does "5w" refer to?
What is the geometry of the system? You have not actually shown us how you attempted the problem  only the numbers you got as a result. 


#3
Feb2812, 07:29 PM

P: 103

what i did was the following: The acceleration is 4.8m/s/s, this is sort of like a railgun. so V_{2}^{2}=v_{1}^{2}+2ad and i plugged in the humbers V_{2}^{2}=(2.8)^{2}+2(4.8)(1) and it turns out that supposedly v_{2}=4.18 when it's supposed to be 2 so now this makes me think why this isn't exactly like a railgun (the velocity decrased) any ideas? for some reason I think this can only be solved with calculus, just a feeling, a weird feeling though... 


#4
Feb2812, 10:30 PM

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Magnetic Flux and Induced Voltage Interesing question
This is why I asked about the geometry  isn't there a slope involved?



#5
Feb2912, 01:48 PM

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