
#1
Mar312, 12:50 PM

P: 181

1. The problem statement, all variables and given/known data
I just need to know if it makes sense; I was told that I can't have anyone make any improvements on what I've written myself. Question: If [itex]X = \{ x_1 , \ldots, x_n \}[/itex] and [itex]Y = \{ y_1 , \ldots, y_m \}[/itex], how many functions from [itex]X[/itex] to [itex]Y[/itex] exist? My answer: [itex]m^n[/itex] functions 3. The attempt at a solution For any element [itex]x \in X[/itex], there exists a unique [itex]y \in Y[/itex] for which [itex]F(x) = y[/itex]. Every [itex]n[/itex] element in [itex[X[/itex] will be paired with any one of the [itex]m[/itex] elements in [itex]Y[/itex]. i.e. there exist [itex]m[/itex] possible [itex]F(x_1)[/itex] in [itex]Y[/itex] that can be paired with [itex]x_1[/itex]. [itex]x_2[/itex] can be paired with [itex]m[/itex] possible [itex]F(x_2)[/itex] [itex]\vdots[/itex] [itex]x_n[/itex] can be paired with [itex]m[/itex] possible [itex]F(x_n)[/itex]. Because the domain [itex]D_F = X[/itex], every function generated through F will contain [itex]n[/itex] coordinate pairs. Furthermore, since there are [itex]m[/itex] possible values [itex]F(x) = y[/itex] for each element [itex]x[/itex], there are [itex]n[/itex] factors of [itex]m[/itex], or [itex]m^n[/itex], possible functions. Thanks for any commentary (but not actual help!) you can provide. 



#2
Mar312, 04:05 PM

Sci Advisor
HW Helper
Thanks
P: 25,170

Makes perfect sense to me.



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