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Proof for: If a|bc, then a|b. |
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| Mar18-12, 08:05 PM | #1 |
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Proof for: If a|bc, then a|b.
In my Discrete Mathematics class we are are covering divisibility. One of the problems that the professor covered (quite terribly) is the following:
1. The problem statement, all variables and given/known data Prove or salvage: If a|bc, then a|b. 2. Relevant equations Relevant concepts: Relatively prime numbers Divisibility 3. The attempt at a solution I know that the statement is wrong as it is. I also know that in order to salvage the statement, I must say that a and c are relatively prime. The problem is that I do not know how to rigorously prove this. Could somebody guide me in how to do this. Teach a man to fish! |
| Mar18-12, 09:48 PM | #2 |
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Use the following fact: If gcd(a,c)=1, then ax+cy=1 for some integers x,y.
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| discrete math, discrete math proofs, proof, prove, salvage |
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