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Projectile motion equation stuck! downwards velocity and angle |
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| Mar19-12, 06:26 AM | #1 |
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Projectile motion equation stuck! downwards velocity and angle
1. A projectile motion is fired horizontally at 150ms-1 from the top of a 196m high cliff. Calculate its velocity on hitting the ground.
2. Okay so ive already discovered its time of flight t = 6.32s and its range Δx = 948m. Other figures are Δy= 196m, ay= -9.8ms-1, ux=150ms-1, Vy= 0ms-1, uy= 61.96ms-1 |
| Mar19-12, 08:27 AM | #2 |
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Hey.All your answers are spot on .
The velocity vector is 150i-62j (rounding 61.96 as 62). So you have the velocity vector.You can find the magnitude of velocity (which I think the question meant by asking the velocity.Speed would have been a better term)and the angle it makes with the horizontal. |
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| angle, horizontal motion, projectile motion, velocity, vertical motion |
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