## Projectile motion equation stuck! downwards velocity and angle

1. A projectile motion is fired horizontally at 150ms-1 from the top of a 196m high cliff. Calculate its velocity on hitting the ground.

2. Okay so ive already discovered its time of flight t = 6.32s and its range Δx = 948m.
Other figures are Δy= 196m, ay= -9.8ms-1, ux=150ms-1, Vy= 0ms-1, uy= 61.96ms-1

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 Hey.All your answers are spot on . The velocity vector is 150i-62j (rounding 61.96 as 62). So you have the velocity vector.You can find the magnitude of velocity (which I think the question meant by asking the velocity.Speed would have been a better term)and the angle it makes with the horizontal.

 Tags angle, horizontal motion, projectile motion, velocity, vertical motion

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