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14 bits at the output means 16 bits -2 on the MSB side? |
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| Mar25-12, 03:36 AM | #1 |
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14 bits at the output means 16 bits -2 on the MSB side?
Just trying to check myself, as 14 bits doesn't seem to make sense...so I wanna see how does it make sense. Is what written at the title true?
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| Mar25-12, 04:42 AM | #2 |
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14 bits means just 14 bits. You dont have to fight war for that.
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| Mar25-12, 04:54 AM | #3 |
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My old system(ca 1973) gave 14 significant bits in its 16 bit word, two MSB's were hardwired together and used for sign . |
| Mar25-12, 05:59 AM | #4 |
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Recognitions:
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14 bits at the output means 16 bits -2 on the MSB side?
If you have to connect 14 bits of output to 16 bits of input, you would typically connect those 14 bits to the 14 least significant bits (lsb), leaving the 2 most significant bits (msb).
So yes, what you wrote at the title is true. |
| Mar25-12, 06:41 AM | #5 |
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Seems simple enough-- thank you.
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| Mar25-12, 12:59 PM | #6 |
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Or is your 'lack of belief' in 14 bits because you expected data to be in two 8bit bytes? |
| Mar25-12, 07:14 PM | #7 |
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Where to connect the 14 bits to 16bits depend on the range you want. Usually for maximum range, you map MSB to MSB so you just map the 14MSB to the MS 14 bits of the 16 bit system. Then you just ground the LS 2 bits. With this, you get the full range of the 16 bit system BUT with only 14 bit resolution.
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