Someone please help me with these symbols?

by c0nfused34235
Tags: impact, physics, variables
 Share this thread:
 P: 4 1. The problem statement, all variables and given/known data I'm doing an impact physics for engineering question and I cannot tell the difference between (v_A)_2x & (v_(Ax))_2. * I don't think I'll need help with solving the actual question if I understand these variables. 2. Relevant equations N/A 3. The attempt at a solution I know that v_A is object A's initial velocity, however, I don't know how to deal with the _2x. As for the second term above, I have no idea.....
Mentor
P: 40,961
 Quote by c0nfused34235 1. The problem statement, all variables and given/known data I'm doing an impact physics for engineering question and I cannot tell the difference between (v_A)_2x & (v_(Ax))_2. * I don't think I'll need help with solving the actual question if I understand these variables. 2. Relevant equations N/A 3. The attempt at a solution I know that v_A is object A's initial velocity, however, I don't know how to deal with the _2x. As for the second term above, I have no idea.....
Welcome to the PF.

Can you post a picture or scan of the use of those symbols?
 Sci Advisor HW Helper Thanks P: 26,148 hi c0nfused34235! welcome to pf! (try using the X2 button just above the Reply box ) you mean (vA)2x & (vAx)2 ? what is the context?
 P: 4 Someone please help me with these symbols? Hi guys, thanks for the warm welcome and quick replies. Here's the question and it's solution. I was trying to figure it out (how they solve it) and I could not understand how they found the 2 variables in the red box (see image attached below). Thanks again. Attached Thumbnails
 HW Helper Thanks P: 5,257 (v_A)2 is the final velocity of body A, i.e., its velocity after the collision (v_A)_2x is the x-component of body A's final velocity after collision (v_(Ax))_2 is the after collision value of A's x-component of velocity The sum of the x-components of momentum of the system before and after the bodies collide remains constant. The same goes for the y-components of momentum.
Sci Advisor
HW Helper
Thanks
P: 26,148
hi c0nfused34235!
 Quote by c0nfused34235 … I could not understand how they found the 2 variables in the red box (see image attached below).
(vA)2x and (vAx)2 are the same

(i've no idea why they've done that )

so they just add (vA)2x + (vB)2x to (vA)2x - (vB)2x to get 2(vA)2x

(and subtract to get 2(vB)2x)
 P: 4 Could someone please solve for one of them (with steps)? I still don't understand how they solve for those variables. If they are indeed identical, why can't I substitute one set into the other formula? I get completely incorrect values.
 P: 4 YES I GOT IT!!! Thanks for your help guys!

 Related Discussions Special & General Relativity 4 Forum Feedback & Announcements 2 Quantum Physics 6 Forum Feedback & Announcements 3