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Someone please help me with these symbols? 
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#1
Mar2912, 01:35 PM

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1. The problem statement, all variables and given/known data
I'm doing an impact physics for engineering question and I cannot tell the difference between (v_A)_2x & (v_(Ax))_2. * I don't think I'll need help with solving the actual question if I understand these variables. 2. Relevant equations N/A 3. The attempt at a solution I know that v_A is object A's initial velocity, however, I don't know how to deal with the _2x. As for the second term above, I have no idea..... 


#2
Mar2912, 01:48 PM

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Can you post a picture or scan of the use of those symbols? 


#3
Mar2912, 01:49 PM

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P: 26,157

hi c0nfused34235! welcome to pf!
(try using the X_{2} button just above the Reply box ) you mean (v_{A})_{2x} & (v_{Ax})_{2} ? what is the context? 


#4
Mar3012, 04:07 AM

P: 4

Someone please help me with these symbols?
Hi guys, thanks for the warm welcome and quick replies. Here's the question and it's solution. I was trying to figure it out (how they solve it) and I could not understand how they found the 2 variables in the red box (see image attached below). Thanks again.



#5
Mar3012, 05:51 AM

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(v_A)_{2} is the final velocity of body A, i.e., its velocity after the collision
(v_A)_2x is the xcomponent of body A's final velocity after collision (v_(Ax))_2 is the after collision value of A's xcomponent of velocity The sum of the xcomponents of momentum of the system before and after the bodies collide remains constant. The same goes for the ycomponents of momentum. 


#6
Mar3012, 07:13 AM

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hi c0nfused34235!
(i've no idea why they've done that ) so they just add (v_{A})_{2x} + (v_{B})_{2x} to (v_{A})_{2x}  (v_{B})_{2x} to get 2(v_{A})_{2x} (and subtract to get 2(v_{B})_{2x}) 


#7
Mar3012, 06:57 PM

P: 4

Could someone please solve for one of them (with steps)? I still don't understand how they solve for those variables. If they are indeed identical, why can't I substitute one set into the other formula? I get completely incorrect values.



#8
Mar3012, 07:23 PM

P: 4

YES I GOT IT!!!
Thanks for your help guys! 


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