## capacitance power factor question.

1. The problem statement, all variables and given/known data

A 50 KW load operates from a 60 Hz 10KV rms line with a power factor of 60% lagging. Determine the capacitance that must be placed in parallel with the load to achieve a 90% lagging power factor.

3. The attempt at a solution

for 60% p.f:-

θ1 = Cos-1(0.6) = 53.13 degrees

Q1 = 50,000*tan(53.13) = 66.667 kVAR

for 90% p.f:-

θ2 = Cos-1(0.9) = 25.84 degrees

Q2 = 50,000*tan(25.84) = 24.22 kVAR

Qcapacitor = Q2 - Q1 = -42.45 kVAR

Xc = VRMS /Qc = (104)2 / -42450 = -2356 Ω

ω = 2.∏.f = 2.∏.60 = 377

C = 1 / ω.Xc = 1 / 377*2356 = 1.126 μF

can anyone check if i'm on the right path here please?

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 anyone?
 Recognitions: Homework Help I posted a response to this about 6 hours ago, saying that's the answer I got. Not sure where my reply went.

## capacitance power factor question.

Ok thats good. thank you

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