
#1
Apr1812, 11:04 AM

P: 656

Please consider
http://gyazo.com/e5c5b4f7808a63e7e664440259ac3058 I agree with all notes made on that slide, but I don't actually get how they constructed the diagram from that? I understand that they line represents frequency so going to 0 to infinity means the line would travel from 0.5 to 0, but HOW DO THEY KNOW what the size values the curve peak at on the imaginary axis??? Further, it says phase decreases from 180 to 270, I agree from the transfer function, but how does this look on the Nyquist diagram? How does phase affect the Nyquist diagram? Thanks EDIT: Apologies if this may seem like a double post 



#2
Apr1912, 07:56 AM

Mentor
P: 11,416

[tex]\frac{1}{(jω + 1)(jω + 2)(jω  1)} = \frac{2}{(1 + ω^2)(4 + ω^2)} + j\frac{ω}{(1 + ω^2)(4 + ω^2)} [/tex] This should help pick out any particular relationships or extrema of the real and imaginary components, as well as phase relationships since ##\phi = tan^{1}(Im/Re)##. 


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