
#1
Apr3012, 05:30 AM

P: 8

1. The problem statement, all variables and given/known data
please i need help as have been trying to solve this question: A body cools from 70°C to 50°C in 6mins when the temp of the surrounding is 30°C. what wil be the tempt of the body after another 12mins if the cooling obeys newtons law of cooling equation: dq/dt = k(θθs) where m mass of the body cspecific heat capacity of the body θtemp of the body θstemp of the surrounding or room 3. The attempt at a solution i tried sovling it as follows: dq=mc(7050) =20mc dq/dt= 20mc/6= k(7050) =20k dq=mc(50θs) dqdt=mc(50θs)/12=k got lost from here please help!!!!! 



#2
Apr3012, 08:20 AM

P: 449

Hi. by relation q=cθ the equation is
dθ/dt = k/c (θθs) solving it θ = (θ0θs) e^k/c t + θs where θ0 is initial temperature of the body. regards. 



#3
Apr3012, 09:03 AM

P: 8

thanks for the help




#4
Apr3012, 11:52 AM

P: 8

need help on this question on Newtons law of cooling
hey,
wouldnt mind if you help me in solving them as regards to the equation given 



#5
Apr3012, 11:58 AM

Mentor
P: 39,615

BTW  I fixed up the "txt speak" abbreviation in your post. We do not allow txt speak abbreviations like "d" or "u" here. Please reread the Rules link at the top of the page. Thanks. 


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