Finding the Zeros of a Polynomial Function

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Homework Help Overview

The discussion revolves around finding the zeros of the polynomial function f(x) = x^4 - 25. Participants explore both graphical and algebraic methods to identify the roots of the equation.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to use a calculator to find zeros but expresses confusion about the results. Some participants suggest algebraic methods, including factoring and deducing potential solutions from the equation.

Discussion Status

Participants are actively discussing various methods to find the zeros, including graphical and algebraic approaches. There is a recognition of the need for precision in the algebraic deductions, and some guidance has been provided regarding factoring the polynomial.

Contextual Notes

There is a mention of potential confusion regarding the identification of zeros, particularly concerning the distinction between real and complex solutions. The original poster's approach using a calculator is noted as potentially limited.

jai6638
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hey.. how would i find the zeros of the following function:

f(x)=x^4-25

I tried inputting the value into my caculator and then go to table find y values that equal 0 in x and i only found -25.. how do i find the rest?


thanks
 
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-25 shouldn't be one of the zeros. You can find the two real zeros graphically, but why not do it algebraically?

x4 - 25 = 0
x4 = 25
x2 = {-5, +5}
and so on...
 
[tex]x^4-25=0[/tex]
[tex]x^4=25[/tex]
[tex]x^2=5[/tex]
[tex]x=+-/sqrt{5}[/tex]
 
Last edited:
hey vitaly, do you by any chance live in Ohio? just guessing...
 
Nope... What makes you say that?
 
i knew a person by the name Vitaly there, but i guess it is a common name.. so i was being unrealistic...
 
Oh, well I live in TN...

Is the person you knew Russian? I have never met anybody else with my name before. Most people think it's weird; it's definitely not common here.
 
yup, they were russians.. infact there was two of them cause they were twins...
 
ok that was a stupid question... didnt think of that for some odd reason.. thanks much for ur help1
 
  • #10
For the sake of precision, from:

x^4 = 25

you should deduce

x^2 = 5 or x^2 = -5

and not just the first one.


Actually, I'm a big fan of using factoring instead of these types of manipulations. e.g.

x^4 = 25
x^4 - 25 = 0
(x^2 - 5)(x^2 + 5) = 0
 
  • #11
To continue from where Hurkyl left off:

[tex]x^{4}-25=(x-\sqrt{5})(x+\sqrt{5})(x-i\sqrt{5})(x+i\sqrt{5})=0[/tex]

I think the solutions are obvious.

Daniel.
 
  • #12
dextercioby said:
To continue from where Hurkyl left off:

[tex]x^{4}-25=(x-\sqrt{5})(x+\sqrt{5})(x-i\sqrt{5})(x+i\sqrt{5})=0[/tex]

I think the solutions are obvious.
Obvious? Probably not to jai6638
 
  • #13
And how did u know that??Did u talk to him?? :wink:

Daniel.
 
  • #14
i got it... thanks much! :)
 
  • #15
dextercioby said:
And how did u know that??Did u talk to him?? :wink:

Daniel.
Well, he(she?) didn't know how to find the zeros of x^4-25. From that I can infer that you statement might not be very obvious to him(her?).
 

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