## Finding the velocity of the wind

1. The problem statement, all variables and given/known data

An airplane travels N40∘E at an airspeed of 1000km/h. Measurement on the ground shows that the plane is travelling N45∘E at a speed of 1050 km/h. Calculate the velocity of the wind.

2. Relevant equations

Vg = Va + Vw

3. The attempt at a solution

so i know we're suppose to use the formula Vg = Va + Vw

we know Vg is 1050km/h N45∘E
and Va is 1000km/h N40∘E
we don't know Vw, so we subtract it to the other side of the equation and we have a subtraction of vectors

I drew my vector diagram, and applied to cos law to get the veloctiy of the wind,

a= sqrt[1050^2 + 1000^2 -2(1000)(1050)cos∘]
and got 102.4 km/h as my wind velocity,

can someone confirm if i'm right? :s

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 Quote by xChee 1. The problem statement, all variables and given/known data An airplane travels N40∘E at an airspeed of 1000km/h. Measurement on the ground shows that the plane is travelling N45∘E at a speed of 1050 km/h. Calculate the velocity of the wind. 2. Relevant equations Vg = Va + Vw 3. The attempt at a solution so i know we're suppose to use the formula Vg = Va + Vw we know Vg is 1050km/h N45∘E and Va is 1000km/h N40∘E we don't know Vw, so we subtract it to the other side of the equation and we have a subtraction of vectors I drew my vector diagram, and applied to cos law to get the veloctiy of the wind, a= sqrt[1050^2 + 1000^2 -2(1000)(1050)cos∘] and got 102.4 km/h as my wind velocity, can someone confirm if i'm right? :s
A good way that you can confirm the answer yourself is to use component-wise subtraction, and convert that back into polar coordinates. Are you familiar with converting back and forth between polar and rectangular coordinates?

 Quote by berkeman A good way that you can confirm the answer yourself is to use component-wise subtraction, and convert that back into polar coordinates. Are you familiar with converting back and forth between polar and rectangular coordinates?
no.... :l

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## Finding the velocity of the wind

 Quote by xChee no.... :l