## undergrad nuclear physics; spin parity rules

Chapter 3 #17 (Krane) The spin-parity of 9Be and 9B are both 3/2-. Assuming in both cases that the spin and parity are characteristic only of the odd nucleon, show how it is possible to obtain the observed spin-parity of 10B(3+). What other spin-parity combinations could also appear? (These are observed as excited states of 10B.)

Here's what I think I know. The parity is (-1)l. So for 9Be and 9B, l = 1. It makes sense that these two nuclei have half-integer spin because A = 9 is odd. It makes sense that 10B has integer spin because A = 10 is even. The fact they're telling me to consider the spin and parity is charactersitic of the odd nucleon is supposed to be hinting at something, but I'm not sure what. I realize 9Be has an extra neutron and one less proton than 9B, but I don't know if I'm supposed to be getting any useful information from the fact that the unpaired particle is a proton in one case and a neutron in the other. If anyone can fill in any of these blanks for me, I would appreciate it.

Aside from this question, and in general, I'm confused about how nucleons pair off and have their spin cancel out with other nucleons. From what I've heard in class so far even numbers of nucleons should just pair off and leave nuclei with either 0 or 1/2 spin. :(

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