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Langevin equation to Fokker Planck |
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| Jun7-12, 06:07 AM | #1 |
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Langevin equation to Fokker Planck
1. The problem statement, all variables and given/known data
This isn't actually homework but I'm really interested in finding the solution. So I have the langevin equation dy/dt = -dV/dy +η(t) where V(y) = -by^3/3 + ζy how can I turn this into a fokker-planck equation? 2. Relevant equations x' = v(x) +η(t) v(x)= -udV/dx 3. The attempt at a solution Using the format of the langevin equation x' = v(x) +η(t), I get x' = -u(bx^2+ζ) + η(t) (( v(x)= -udV/dx )) Which I don't know how to solve in closed form. Any ideas/suggestions? Thanks! |
| Jun7-12, 08:06 AM | #2 |
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Your differential equation is in the "standard form"
[tex] dy = -b y^2 dt + dB [/tex] For a generic SDE, we have [tex]dx = b(t,x) dt + a(t,x) dB[/tex] and the corresponding Fokker-Planck equation is [tex] \frac{\partial f(t,x)}{\partial t} = - \frac{\partial}{\partial x} (b(t,x) f(t,x)) + \frac{1}{2} \frac{\partial^2}{\partial x^2} (a^2(t,x) f(t,x)) [/tex] |
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