Projectile Motion Problem This problem is completely evading me.

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Homework Help Overview

The problem involves calculating the angle at which William Tell must aim to hit an apple atop his son's head from a distance of 27.8 m, with the arrow traveling at a speed of 34.6 m/s. The context is projectile motion, specifically focusing on the relationship between horizontal distance and vertical motion under gravity.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to derive the angle using the formula sin 2(theta) = Rg/(velocity initial squared) and expresses confusion over receiving incorrect answers from the homework engine. Some participants question whether the answers should be in radians and discuss the existence of two potential solutions.

Discussion Status

Participants are exploring the calculations and interpretations of the problem. There is a suggestion that the original poster's calculations may be correct, and some guidance is offered regarding the possibility of needing to express answers in radians. The discussion includes multiple interpretations of the results, particularly concerning the two angles derived.

Contextual Notes

There is mention of a homework engine providing feedback on the answers, which may imply specific formatting or answer requirements that are not fully clarified. The original poster's calculations are noted as potentially messy, and there is uncertainty about the expectations for multiple solutions.

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William Tell must split the apple atop his son's head from a distance of 27.8 m. When he aims directly at the apple, the arrow is horizontal. At what angle must he aim it to hit the apple if the arrow travels at a speed of 34.6 m/s?

This sounds extremely simple, and I thought I got the answer at first. However, the homework engine at my college keeps saying I got the answer wrong.

Here's how I did it:

Vyot - 1/2gt^2 = 0

I solve for t, and get t=0 and t=2Vyo/g

I plug the second t in the x-cordinate for horizontal motion.

R = x = Vxot = Vxo(2Vyo/g) = (2VxoVyo)/g = (2V^2o sin(theta)o cos(theta)o)/g)

Eh, the work is messy but I'll skip down to my final deriviation and that is:

sin 2(theta) = Rg/(velocity initial squared)
(This is a common formula and the book uses this same formula to solve similar problems like this. And the funny thing is that I can follow their answers using that equation, but I apparently don't get a correct answer when I'm using it in this problem.)

I plugged in all the information I got and received 6.58 degrees and 84.3 degrees. There are two answers, and I typed both of them in the homework engine, and it said they were wrong. What am I doing wrong?
 
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Here's a picture just to help.

This is basically what I'm doing and I'm still apparently getting the wrong answer, lmao!

http://img158.exs.cx/my.php?loc=img158&image=0501252243177jy.jpg
 
I think your answer is correct. Maybe the answer is supposed to be in radians?
 
The answer should be roughly [itex]0.114 rad[/itex] which is approx.the number you found (+6.5°).

Daniel.


P.S.How did you find 2 solutions??
 
Last edited by a moderator:
dextercioby said:
The answer should be roughly [itex]0.114 rad[/itex] which is approx.the number you found (+6.5°).

Daniel.


P.S.How did u find 2 solutions??

Oops... I didn't notice the second solution he had. The 84.3 degrees is wrong. Is the computer expecting two answers?
 

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