How do I calculate the instantaneous velocity

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Homework Help Overview

The discussion revolves around calculating instantaneous velocity from a distance-time graph, focusing on identifying slope breaks and the method for determining instantaneous velocity at those points.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to understand how to calculate instantaneous velocity at slope breaks on a d-t graph, questioning whether to use tangent lines or points for calculation. Some participants inquire about the original poster's background in calculus and derivatives.

Discussion Status

Participants are exploring different methods to identify slope breaks and calculate instantaneous velocity. Some guidance has been offered regarding the use of derivatives, but there is no explicit consensus on the best approach yet.

Contextual Notes

The original poster expresses confusion about finding slope breaks and calculating instantaneous velocity, indicating a potential gap in understanding calculus concepts related to derivatives.

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I've constructed a d-t graph and the question is, how do I calculate the instantaneous velocity, vinst, for each slope break? How do I find the slope break? Do I calculate it using v=chginx/chgint formed by the tangent line to the point or using the point alone simular to Vavg. I've drawn tangent lines to the peaks of the curves and computed rise over run with incorrect results.
 
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Have you taken calculus, or do you know how to take derivatives?
 
vinst

you have the movement equation? if you have it and you have taken calculus you must know the vinst ist the first derivative of the function evaluated at the point you want to calculate vinst.
 
Thanks. I was puzzled as to where to find the slope breaks. Once I graphed this out, I saw several linear lines that crossed each other along the graph and it was at these points I calculated Vinst.
 

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