Calculate % Silicon in Silicate Mineral | Danne

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Discussion Overview

The discussion revolves around calculating the percentage of silicon in a silicate mineral based on given weights of silicon oxide and the mineral itself. Participants explore various approaches to the problem, including mathematical reasoning and clarifications on chemical formulas.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • One participant, Danne, asks how to calculate the percentage of silicon in a silicate mineral given specific weights.
  • Another participant suggests that Danne should attempt the problem first before seeking help.
  • Several participants discuss the formula for calculating the percentage of silicon, with one proposing a formula involving the weights of silicon and silicon oxide.
  • There is confusion regarding the correct interpretation of silicon oxide versus silicon dioxide, with participants debating the implications of this distinction.
  • One participant calculates a percentage of silicon based on a formula but receives feedback that their answer may be incorrect.
  • Another participant provides a step-by-step approach to finding the percentage of silicon, emphasizing the relationship between silicon and silicon dioxide.
  • Participants engage in correcting and refining each other's calculations and assumptions throughout the discussion.
  • At one point, a participant expresses uncertainty about the calculations and requests further hints.
  • Finally, a participant arrives at a percentage of approximately 39% and seeks confirmation of their result.

Areas of Agreement / Disagreement

There is no clear consensus on the correct approach or final answer, as participants present differing calculations and interpretations of the problem. Some participants agree on the need to clarify the distinction between silicon oxide and silicon dioxide, while others challenge the calculations presented.

Contextual Notes

Participants express uncertainty about specific calculations and the definitions of chemical compounds involved. There are unresolved assumptions regarding the weights and the correct formulas to use in the calculations.

Who May Find This Useful

This discussion may be useful for students or individuals interested in chemistry, particularly those studying silicate minerals and the calculations involved in determining elemental percentages in compounds.

danne89
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Hi!
How many per cent of silicon is there in a silicate mineral, if 0.567 g during analysis gave 0.484 silicon oxide.

Gratefull,
Danne
 
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danne,

We really can not help you unless you first make an attempt. What ideas do u have ?
 
Oh, I'm sorry. But I've not any cloue.
 
Okay.
[tex]percentage \ Si =\frac{m_{Si}}{m_{compound}}\cdot 100[/tex]

Daniel.
 
Ask yourself : how much Si is there in SiO2 ?
 
Okej, I've: % Si = Si:Si02 * 100 = 2800:60 ~= 47%

So the weight information's only purpose is to trick you? :(
 
No,its purpose is to help answer the problem's question.Reread its text and see what it needs to be done.

Daniel.
 
(0.567 * Si * 100):(0.484 * Si02) = (56.7 * 28):(0.484 * 60) = 1588:29.04 ~= 55%
Sorry for the amount of numbers, I'm using log-table.
 
I'm sorry,u have no reason to applogize,even after coming up,again,with a wrong answer.

My answer is "roughly 40%".

Daniel.
 
  • #10
danne89 said:
Hi!
How many per cent of silicon is there in a silicate mineral, if 0.567 g during analysis gave 0.484 silicon oxide.

Gratefull,
Danne

What's the unit of .484 ? grams?
 
  • #12
dextercioby said:
No,MeV/c^{2}... :-p

Daniel.

alright... I don't get 40 % when i try this problem out.

SiO2 = total weight

SiO =.484 grams

O = Total weight - .484 + (weight of O inside Silicon oxide)

Well we know how much Oxygen is in there we can easily figure out the percentage of Si...

dextercioby said:
I'm sorry,u have no reason to applogize,even after coming up,again,with a wrong answer.

My answer is "roughly 40%".

I don't get 40 %... I think you've mistaken SiO for SiO2 (silicon oxide not dioxide)
 
Last edited:
  • #13
Of course it's [itex]SiO_{2}[/itex].

Daniel.

P.S.Does Silicium form oxides at +2??My guess is "no"...
 
  • #14
% Si = (0.567 * Si * 100):(0.484 * Si*Si02) = (56.7 * 28):(0.484 * (28 + 28 + 2 * 16)) = 1587.6:(0.484 * 88) = 42.59%

Yes! At least my slow head isn't act as a fools mind.
 
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  • #15
Explain that part:
[tex](28+28+2*16)[/tex]

Why on Earth did u add 28 TWICE?

Daniel.

P.S.Is it [tex]Si_{2}O_{2}[/tex] ??
 
  • #16
I add the Si and Si02 together.
Edit: Which seems to be quite idiotic now...
 
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  • #17
Can I have some more hint?
 
  • #18
Why would you do that for?It's only SiO_{2} in the mineral.It has the molecular mass of 60 and it's content of Si is
[tex]\frac{28}{60}[/tex]

Is that enough ?

Daniel.
 
  • #19
No. I can't solve it.
 
  • #20
Okay.Here goes:
28g Si---------------------------->60g SiO_{2}
x g Si------------------------------>0.484g SiO_{2}

Find "x" and then:

x g Si-------------------------->0.567g mineral
y g Si-------------------------->100g mineral

Find "y".That will be the answer to your problem
"y"% Si in the mineral...

Daniel.
 
  • #21
So the answer is ~ 39% But I don't understand this. Can you redirect me to a good site, I've search a bit on google already.
 
  • #22
I'm sorry,but i don't follow...Good site on what??And what exactly didn't u understand??

Daniel.
 
  • #23
danne89 said:
So the answer is ~ 39% But I don't understand this. Can you redirect me to a good site, I've search a bit on google already.

danne, this is not very hard, and you've nearly got it. I'm quite sure that the question really means "silicon dioxide" rather than "silicon oxide". All silicates (that I know of at least - like sodium, potassium, aluminum,...) are composed of SiO2 units, so this must be what they are talking about.

First of all you found out how much Si there is in SiO2. You got this to be about 46.7%. This simply means that every 100g of SiO2 will contain 46.7g of Si.

But you are told how much SiO2 there is (0.484g), so you can determine how much Si there should be in 0.484g of SiO2. This will just be 46.7% of 0.484g. What does that give you ? Divide this number by the total weight to get the required percentage.

You should get about 39.8%
 
  • #24
46.7 * 0.484 : 0.567 = 22.6028:0.567 = 39.86 %
I'm a right now?
 
  • #25
Yes, that's right. But you have to divide the left side by 100 to account for the percentage.
 

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