Proportional Resistive Force Problem

Click For Summary
SUMMARY

The discussion focuses on the resistive force acting on a speed skater, modeled by the equation f = -kmv², where k is a constant and m is the mass of the skater. The skater's speed after crossing the finish line is derived as Vf = Vi / (1 + Vi * k * t). The participants clarify that while a differential equation can be used, the problem can also be approached through straightforward integration, leading to the integral form 1/V(t) - 1/Vi = -kt.

PREREQUISITES
  • Understanding of Newton's Second Law (mass times acceleration equals force)
  • Familiarity with differential equations and integration techniques
  • Knowledge of resistive forces and their mathematical representation
  • Basic principles of kinematics in physics
NEXT STEPS
  • Study the derivation of differential equations in physics applications
  • Explore integration techniques relevant to physics problems
  • Learn about resistive forces and their impact on motion
  • Investigate real-world applications of proportional resistive forces in sports
USEFUL FOR

Physics students, educators, and anyone interested in the mathematical modeling of motion and forces, particularly in sports dynamics.

Nitrus
Consider an object which the net force is a resistive force proportional to the square of its speed. For example: assume that the resistive force acting on a speed skater is f=-kmv^2, where k is a constant and m is the skater's mass. The skater corsses the finish line of a straight-line race with speed v(i) and the slows down by coasting on his skates. Show that his speed at time "t", any time after the finish line is equal to Vf=Vi/(1+Vi*k*t).

Do i need to do a diff eq for this?
 
Physics news on Phys.org
I don't know that you NEED a differential equation- it's a pretty straight forward integration- but it might be simpler to think of it as a differential equation.

The basic law is, of course, "mass times acceleration equals force". Here, you are told that the force is kmv2 so

m dv/dt= km v2 (yep, that's a differential equation!)
which you can immediately write as

v-2 dv= k dt (Now it's an integral problem!)

Integrate both sides. Be careful about the constant of integration.
 
yeah i figured it out... you take the definite integral of the right side from t to 0, then on the left you do as V-knot goes to V(t). which will give you:

1/V(t)-1/Vi=-kt

which then simplifies to what I am looking for
 

Similar threads

Replies
2
Views
2K
Replies
7
Views
6K
  • · Replies 3 ·
Replies
3
Views
3K
Replies
12
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 37 ·
2
Replies
37
Views
5K
  • · Replies 6 ·
Replies
6
Views
9K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 6 ·
Replies
6
Views
1K
  • · Replies 7 ·
Replies
7
Views
3K