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Combinatorics - Mathematical Induction? |
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| Jun15-12, 12:59 PM | #1 |
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Combinatorics - Mathematical Induction?
Hello, I am having trouble solving this problem. Maybe I'm just overreacting to it. In my two semesters in discrete math/combinatorics, I've never seen a problem like this (with two summations) and been asked to prove it. Can some one help?
[itex]\sum^{n}_{i=1} i^3 = \frac{n^2(n+1)^2}{4} = (\sum^{n}_{i=1} i)^2[/itex] I mean, I know the whole S(n), S(1), S(k), S(k+1) steps, but I'm just unsure of how to write it. The solutions manual for the book skip that problem. Book: Discrete And Combinatorial Mathematics: An Applied Introduction by Ralph P. Grimaldi, 5th Edition. |
| Jun15-12, 02:22 PM | #2 |
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First of all, this is a textbook problem, so it belongs in the homework forums. I moved it for you
![]() Second, you actually need to show two things: [tex]\sum_{i=1}^n i^3=\frac{n^2(n+1)^2}{4}[/tex] and [tex]\sum_{i=1}^n i = \frac{n(n+1)}{2}[/tex] (and square both sides) Can you do that? |
| Jun15-12, 02:58 PM | #3 |
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Thank you very much! That helped a lot, I just finished my proof. :D That makes sense why you'd have to break it up. I didn't put the relationship between [itex]\sum^{n}_{i=1}i = \frac{n(n+1)}{2}[/itex] and [itex](\sum^{n}_{i=1}i)^2 = \frac{n^2(n+1)^2}{4}[/itex] together. lol
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| Jun15-12, 04:01 PM | #4 |
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Recognitions:
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Combinatorics - Mathematical Induction?The question belongs in mathematics, not computer science. |
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