The discussion revolves around calculating the kinetic energy of a particle, specifically a helium nucleus, as it accelerates from a point of higher electric potential (+290 V) to a point of lower electric potential (-220 V). The context involves concepts of electric potential and kinetic energy in the realm of electromagnetism.
Some participants have suggested methods for approaching the problem, including the use of energy conservation principles and the kinetic energy work theorem. There is an ongoing exploration of the potential difference and its effect on the kinetic energy of the particle, with no explicit consensus reached yet.
Participants are working with specific values of electric potential and the characteristics of the helium nucleus, including its charge. There is an emphasis on understanding the implications of these values in the context of the problem, but no additional information has been provided to resolve the discussion.
The potential difference between a and b is the energy/unit charge: ie. the energy that a unit charge gains in moving from a to b. The energy that a charge of e gains in moving through a potential difference of 1 volt is 1 eV. So what is the energy that a +2e charge gains in moving from a to b?gekdvb said:point a is at a potentiall of +290...point b is at potential of -220...helium nucleus contains 2 neutrons and 2 protons...neutrons are electrically neutral...what kinetic energy does particle have after accelerating from rest at point a to b...in electron volts
gekdvb said:point a is at a potentiall of +290...point b is at potential of -220...helium nucleus contains 2 neutrons and 2 protons...neutrons are electrically neutral...what kinetic energy does particle have after accelerating from rest at point a to b...in electron volts