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Why cos 90 is 0?by Bin Qasim
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#1
Jan2805, 07:11 PM

P: n/a

Hello everyone
got one question here........... why cos 0 is 0? cos of any angle is adjescent by hypotenuse. so what is adjescent in case of 90 degree angle?? is the question clear? please reply ASAP.........pls thanx in advance...... 


#2
Jan2805, 07:18 PM

P: 506

A better definition of cosine is that of a simple period. Given a point on the unit circle, and a radial line segment making an angle t with the positive xaxis, the xcoordinate of the point of intersection is cos(t). The ycoordinate is sin(t). From this visualization, many theorems should be immediately apparent.
PS. Also, sin(0) is 0. cos(0) is 1, as you can see from the circle. 


#3
Jan2805, 07:56 PM

P: 728

Yes, as hypermorphism stated, the definitions of cosine and sine are not really about right trianges: they're about rotation. Now, you know that the argument of sin and cos are angles, correct (for your purposes, of course)? That is, they take in an angle and spit out a "regular" value.
Now, imagine that you have a coordinate plane. You construct that angle you want at the origin and draw a ray that comes out of it. At some point, it will intersect a circle with an arbitrary radius r. Now, imagine that you take that point, and find its coordinates. Call them (x,y). Sine is defined to be the y coordinate divided by the radius of the circle, and cosine is defined to be the x coordinate divided by the radius. (See the attached picture for clarification). What does that mean for us? Since we can draw an angle of any size we want, sin and cos can be defined for any angle, not just the angles between 0 and 90 degrees! We can find the sine of, 10 degrees, 270 degrees, whatever: it doesn't matter. Anyway, you might be wondering, "So, how does this apply to what I though cos was, adjacent over hypotenuse?" Take a closer look at the picture I drew. Imagine that you were only considering the angles in the first quadrant, i.e., when they are between 0 and 90 degrees. Cosine would be defined to be x/r. However, if you think about it, every coordinate on the plane can have a line dropped down from it, to the xaxis. This forms a right triangle, with legs of length x and y and hypotenuse of length r. Can you see where I'm going with this? The leg closest to the angle, the "adjacent" one, has length x. The hypotenuse has length r. Therefore, adjacent/hypotenuse = x/r. Now, back to your original question. From the picture provided, it's obvious that the ray drawn at 90 degrees intersects the circle on the yaxis. Therefore, the coordinates of the intersection point are (0,r) (where r is the radius of the circle again). Thus, x=0, and cos(90 degrees) = x/r = 0/r = 0. 


#4
Jan2905, 08:50 PM

P: n/a

Why cos 90 is 0?
Thank you mates........



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