Why is cos 90 Degrees Equal to 0?

  • Context: High School 
  • Thread starter Thread starter Bin Qasim
  • Start date Start date
  • Tags Tags
    Cos
Click For Summary

Discussion Overview

The discussion revolves around the question of why the cosine of 90 degrees is equal to 0. It explores definitions and interpretations of the cosine function, particularly in relation to the unit circle and right triangles.

Discussion Character

  • Exploratory
  • Technical explanation
  • Conceptual clarification

Main Points Raised

  • One participant questions the definition of cosine as adjacent over hypotenuse in the context of a 90-degree angle.
  • Another participant offers a definition of cosine based on the unit circle, stating that cosine corresponds to the x-coordinate of a point on the circle at a given angle.
  • A further explanation emphasizes that sine and cosine are defined for any angle, not just those between 0 and 90 degrees, and illustrates how cosine can be derived from coordinates on the unit circle.
  • The same participant concludes that at 90 degrees, the ray intersects the y-axis, resulting in an x-coordinate of 0, thus cos(90 degrees) equals 0.

Areas of Agreement / Disagreement

Participants generally agree on the definitions of sine and cosine in relation to the unit circle, but the initial question regarding the interpretation of cosine at 90 degrees reflects some uncertainty and exploration of definitions.

Contextual Notes

The discussion highlights the transition from traditional definitions of cosine in right triangles to a more general understanding involving the unit circle, indicating a potential limitation in the initial framing of the question.

Bin Qasim
why cos 90 is 0??

Hello everyone

got one question here... why cos 0 is 0?

cos of any angle is adjescent by hypotenuse. so what is adjescent in case of 90 degree angle??

is the question clear? please reply ASAP...pls

thanx in advance...
 
Mathematics news on Phys.org
A better definition of cosine is that of a simple period. Given a point on the unit circle, and a radial line segment making an angle t with the positive x-axis, the x-coordinate of the point of intersection is cos(t). The y-coordinate is sin(t). From this visualization, many theorems should be immediately apparent.

PS. Also, sin(0) is 0. cos(0) is 1, as you can see from the circle.
 
Yes, as hypermorphism stated, the definitions of cosine and sine are not really about right trianges: they're about rotation. Now, you know that the argument of sin and cos are angles, correct (for your purposes, of course)? That is, they take in an angle and spit out a "regular" value.

Now, imagine that you have a coordinate plane. You construct that angle you want at the origin and draw a ray that comes out of it. At some point, it will intersect a circle with an arbitrary radius r. Now, imagine that you take that point, and find its coordinates. Call them (x,y). Sine is defined to be the y coordinate divided by the radius of the circle, and cosine is defined to be the x coordinate divided by the radius. (See the attached picture for clarification). What does that mean for us? Since we can draw an angle of any size we want, sin and cos can be defined for any angle, not just the angles between 0 and 90 degrees! We can find the sine of, -10 degrees, 270 degrees, whatever: it doesn't matter.

Anyway, you might be wondering, "So, how does this apply to what I though cos was, adjacent over hypotenuse?" Take a closer look at the picture I drew. Imagine that you were only considering the angles in the first quadrant, i.e., when they are between 0 and 90 degrees. Cosine would be defined to be x/r. However, if you think about it, every coordinate on the plane can have a line dropped down from it, to the x-axis. This forms a right triangle, with legs of length x and y and hypotenuse of length r. Can you see where I'm going with this? The leg closest to the angle, the "adjacent" one, has length x. The hypotenuse has length r. Therefore, adjacent/hypotenuse = x/r.

Now, back to your original question. From the picture provided, it's obvious that the ray drawn at 90 degrees intersects the circle on the y-axis. Therefore, the coordinates of the intersection point are (0,r) (where r is the radius of the circle again). Thus, x=0, and cos(90 degrees) = x/r = 0/r = 0.
 

Attachments

  • graph.GIF
    graph.GIF
    4.2 KB · Views: 3,028
Thank You

Thank you mates... :smile:
 

Similar threads

  • · Replies 12 ·
Replies
12
Views
5K
  • · Replies 38 ·
2
Replies
38
Views
7K
  • · Replies 7 ·
Replies
7
Views
2K
Replies
11
Views
3K
  • · Replies 29 ·
Replies
29
Views
6K
  • · Replies 4 ·
Replies
4
Views
4K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 12 ·
Replies
12
Views
5K
  • · Replies 19 ·
Replies
19
Views
7K