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Lagrangian, particle/magnetic need solution check

 
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Jul2-12, 10:52 PM   #1
 

Lagrangian, particle/magnetic need solution check


Preparing for classical prelim, just wondering if this solution is correct.

1. The problem statement, all variables and given/known data
A particle with mass m and charge q moves in a uniform magnetic field [itex]\boldsymbol{B}=B\boldsymbol{\hat{z}}[/itex]. Write a Lagrangian describing the motion of the particle in the xy plane that gives the correct Lorentz-force equation of motion,
[itex]m\mathbf{a}=q\mathbf{v}\times\mathbf{B}[/itex]

2. Relevant equations
L=T - U

[itex]\frac{d}{dt}\left(\frac{\partial L}{\partial \dot{q}}\right)=\frac{\partial L}{\partial q}[/itex]

[itex]\boldsymbol{B}=\boldsymbol{\nabla \times A}[/itex]

[itex]\boldsymbol{E}=-\boldsymbol{\nabla}\phi +\frac{\partial \boldsymbol{A}}{\partial t}[/itex]

3. The attempt at a solution
I'm going to start with the complete lorentz force and remove the electric potential from the lagrangian later.

[itex]\mathbf{F}=q(\mathbf{E}+\mathbf{v}\times\mathbf{B})[/itex]

[itex]\mathbf{F}=q(\mathbf{E}+\mathbf{v}\times (\boldsymbol{\nabla \times A}))[/itex]

[itex]\mathbf{F}=q(\mathbf{E}+\boldsymbol{\nabla} (\mathbf{v.A})-\boldsymbol{A}(\boldsymbol{\nabla . v}))[/itex]

[itex]\mathbf{F}=q(-\boldsymbol{\nabla}\phi+\frac{\partial\boldsymbol{A}}{\partial t}+\boldsymbol{\nabla}(\boldsymbol{v.A})-\boldsymbol{A}(\boldsymbol{\nabla v}))[/itex]

[itex]U=q(\phi -\boldsymbol{v.A})=q\phi-q\boldsymbol{v.A}[/itex]

We are only interested in the magnetic field so we'll ignore [itex]q\phi[/itex].

[itex]U=q\boldsymbol{v.A}[/itex]

[itex]L=\frac{1}{2}mv^{2} + q\boldsymbol{v.A} \hspace{2 mm}\mathbf{:Answer}[/itex]

As always thanks for the help!
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Jul5-12, 12:58 PM   #2
 
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Quote by AbigailM View Post

[itex]\mathbf{F}=q(\mathbf{E}+\mathbf{v}\times (\boldsymbol{\nabla \times A}))[/itex]

[itex]\mathbf{F}=q(\mathbf{E}+\boldsymbol{\nabla} (\mathbf{v.A})-\boldsymbol{A}(\boldsymbol{\nabla . v}))[/itex]
This is correct, but you should explain how you got it (i.e that you used a specific vector product rule and that 2 of the terms were zero and why) on your exam if you want full marks.

[itex]\mathbf{F}=q(-\boldsymbol{\nabla}\phi+\frac{\partial\boldsymbol{A}}{\partial t}+\boldsymbol{\nabla}(\boldsymbol{v.A})-\boldsymbol{A}(\boldsymbol{\nabla v}))[/itex]

[itex]U=q(\phi -\boldsymbol{v.A})=q\phi-q\boldsymbol{v.A}[/itex]
Your choice of generalized potential is not immediately obvious when looking at this. How did you choose [itex]U[/itex] from this when there are 2 other terms present that depend on your generalized coordinates, momenta and time? There is a step missing in between which will make the choice of [itex]U[/itex] much easier to argue.

[itex]L=\frac{1}{2}mv^{2} + q\boldsymbol{v.A} \hspace{2 mm}\mathbf{:Answer}[/itex]

As always thanks for the help!
Did you actually show that this choice of Lagrangian gives the correct force law?

I only see an incomplete motivation for choosing such a Lagrangian, and no calculations to show that it is indeed a correct choice.
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