Sum of the first n natural numbers is n(n+1)/2

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SUMMARY

The sum of the first n natural numbers is expressed as n(n+1)/2. The discussion explores alternative representations of the product of the first n natural numbers without using the factorial symbol. It highlights the relationship between products and sums through the natural logarithm, specifically ln(n!) = Σln n, and introduces the Gamma function as a method to express factorials, where n! = Gamma(n+1) = ∫(tx-1e-t)dt from 0 to infinity.

PREREQUISITES
  • Understanding of natural numbers and their properties
  • Familiarity with logarithmic functions
  • Knowledge of the Gamma function and its applications
  • Basic calculus, particularly integration techniques
NEXT STEPS
  • Study the properties of the Gamma function and its relationship to factorials
  • Learn about the natural logarithm and its applications in mathematics
  • Explore the concept of limits and their connection to sums and integrals
  • Investigate alternative methods for representing products and sums in mathematics
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Mathematicians, students studying calculus, and anyone interested in advanced mathematical concepts related to summation and factorials.

StephenPrivitera
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We know that the sum of the first n natural numbers is n(n+1)/2

Can we express the product of the first n natural numbers without using the factorial symbol?
It is possible to write a factorial as a sum. Any idea what it would look like?
 
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To my knowledge, there isn't any convenient way.

You can do a "cheap" conversion from a product to a sum, though:

ln Πf(n) = Σln f(n)

So for factorials:

ln(n!) = Σln n
or
n! = eΣln n
 
Another way to write a factorial as a sum (which, I admit, sounds like cheating) is to use the Gamma function.

n! = Gamma(n+1) = Integral(tx-1e-t)dt

(the integral goes from zero to infinity)

Since an integral is the limit of a sum, it is kinda what you wanted.
 

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