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Finding the distance given the intital velocity and the coefficient of friction |
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| Jul8-12, 04:06 PM | #1 |
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Finding the distance given the intital velocity and the coefficient of friction
1. The problem statement, all variables and given/known data
A car is travelling at 15.5m/s travels on a surface where μ=0.1. The driver sees a boy run into the road 125 m ahead. She immedietly applies the brakes, locking the wheel, and skids to a stop. Where will the car be when it stops? (i.e:Will it hit the boy?) I know I should start by figuring out the acceleration and then use Vfinal^2=V inital^2 + 2ad But, I am having trouble finding the acceleration. 2. Relevant equations Fnet=ma Ffriction= μFN Vfinal^2=V inital^2 + 2ad 3. The attempt at a solution |
| Jul8-12, 05:04 PM | #2 |
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hi lenalee.9520! welcome to pf!
![]() (try using the X2 button just above the Reply box )then find the force, and divide by m ![]() (the force will be µ times … ? )
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| Jul8-12, 05:27 PM | #3 |
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Well I ended up with
Ffriction= -mgµ Is this correct? |
| Jul8-12, 05:34 PM | #4 |
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Finding the distance given the intital velocity and the coefficient of friction
call the mass "m" !!
![]() (it'll cancel out in the end) |
| Jul8-12, 06:09 PM | #5 |
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Ffriction= -mgµ
Is what I got... But how does it cancel out?? |
| Jul8-12, 06:42 PM | #6 |
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You could identify it as an energy related problem.
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| Jul8-12, 06:44 PM | #7 |
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| Jul8-12, 06:53 PM | #8 |
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As tiny-tim said, call the mass 'm'
Then if you apply force to it, what is the acceleration? |
| Jul8-12, 07:01 PM | #9 |
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[itex]\sum[/itex]F = ma = [itex]\mu[/itex]kmg
Once you solve for the acceleration, the rest is just a 'timeless' kinematics problem. Vf2 = 0 = Vo2 + 2aΔx |
| Jul9-12, 09:09 AM | #10 |
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| dynamics, forces, kinematics, stopping distance |
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