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taylor prob |
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| Jul29-12, 10:29 AM | #1 |
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taylor prob
i really need help with this prob f(x)=1/1-2x i have to calculate T2(x) at -1 on the interval -1.5,-1 with an error less than 1/80.
I got f"'=48/(1-2x)^4 and f"'(-1.5)=3/16 and i cant get the error at 1/80 . Thank you |
| Jul29-12, 03:29 PM | #2 |
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Mentor
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There are several methods to give an upper bound on the error. The one I would use requires the (n+1)th derivative at some point in the interval - take the point where the absolute value of the derivative has the largest value for an upper bound.
Does this help to fill the gaps in your answer? |
| Jul30-12, 03:51 AM | #3 |
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yep, thank you
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