- #1
leolaw
- 85
- 1
Suppose that electrical attraction, rather than gravity, were responsible for holding the MOon in orbit around the Earth. If equal and opposite charges Q were placed on the Earth and the Moon, what should be the value of Q to maintain the present orbit? Given these data: Moon = [tex]7.35 \ast 10^{22} kg[/tex], Earth = [tex]5.98 \ast 10^{24} kg[/tex] , radius of orbit = [tex]3.84 \ast 10^8 m[/tex].
This is how I approach the problem:
I set
[tex]G \frac{m_{1}m_{2}}{r^2} = k \frac{Q^2}{r^2}[/tex]
and then solve for Q
Am I doing the right thing?
This is how I approach the problem:
I set
[tex]G \frac{m_{1}m_{2}}{r^2} = k \frac{Q^2}{r^2}[/tex]
and then solve for Q
Am I doing the right thing?
You can build a new one,just for the fun of it.However,you won't need the new one exactly to solve your problem...
I was referring to the Law of Gravity (of Universal Attraction).
