courtrigrad
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Hello all
Let's say we have [tex]\frac{1}{\sqrt{2\pi}} e^{\frac{-1}{2\phi^2}}[/tex] where [tex]\phi[/tex] is a standarized normal variable. Let [tex]R_{i} = \frac{S_{i+1} - S_{i}}{S_{i}}[/tex]Also let's say we have a time step [tex]\delta t[/tex] and the mean of the returns scaled with the timestep.Then mean = [tex]\mu\delta t[/tex]
Then why does [tex]\frac{S_{i+1}-S_{i}}{S_{i}} = \mu\delta t[/tex]? Isn't this supposed to be a z-score? Also suppose we want to know how the standard deviation scales with the timestep [tex]\delta t[/tex] The sample standard deviation is [tex]\sqrt{\frac{1}{M-1}\sum^M_{i=1}(R_{i}-R)^2}[/tex] How do we use this to get standard deviation = [tex]\sigma\delta t^{\frac{1}{2}}[/tex]
Also why does [tex]R_{i} = \mu\delta t + \sigma\phi\delta t ^{\frac{1}{2}}[/tex]?
Thanks
Let's say we have [tex]\frac{1}{\sqrt{2\pi}} e^{\frac{-1}{2\phi^2}}[/tex] where [tex]\phi[/tex] is a standarized normal variable. Let [tex]R_{i} = \frac{S_{i+1} - S_{i}}{S_{i}}[/tex]Also let's say we have a time step [tex]\delta t[/tex] and the mean of the returns scaled with the timestep.Then mean = [tex]\mu\delta t[/tex]
Then why does [tex]\frac{S_{i+1}-S_{i}}{S_{i}} = \mu\delta t[/tex]? Isn't this supposed to be a z-score? Also suppose we want to know how the standard deviation scales with the timestep [tex]\delta t[/tex] The sample standard deviation is [tex]\sqrt{\frac{1}{M-1}\sum^M_{i=1}(R_{i}-R)^2}[/tex] How do we use this to get standard deviation = [tex]\sigma\delta t^{\frac{1}{2}}[/tex]
Also why does [tex]R_{i} = \mu\delta t + \sigma\phi\delta t ^{\frac{1}{2}}[/tex]?
Thanks
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