# please help how do i go about solving this??

by the_d
Tags: solving
 P: 130 undefinedundefinedundefined A jogger runs in a straight line with an average velocity of 4:7 m/s for 5.1 min, and then with an average velocity of 4.1 m/s for 3 min. What is her total displacement? Answer in units of meters
P: 213
 Quote by the_d undefinedundefinedundefined A jogger runs in a straight line with an average velocity of 4:7 m/s for 5.1 min, and then with an average velocity of 4.1 m/s for 3 min. What is her total displacement? Answer in units of meters
use the formula:
$$d = V_{average}t$$
 P: 130 and then I subtract the two to find the final displacement
Sci Advisor
HW Helper
P: 11,833

## please help how do i go about solving this??

No,you have to add the 2 distances.

Daniel.
P: 213
 Quote by the_d and then I subtract the two to find the final displacement
Well, it all depends what the direction is. If he runs in the same direction both times, you have to add the 2 displacements to find the total displacement.
 P: 130 thanks dude
 Sci Advisor HW Helper P: 11,833 Even if the runs in the opposite direction on the second time interval,the TOTAL distance would still be gotten by adding the 2. Daniel.
P: 213
 Quote by dextercioby Even if the runs in the opposite direction on the second time interval,the TOTAL distance would still be gotten by adding the 2. Daniel.
Aren't the words "distance travelled" and "displacement" different. I though displacement meant distance and direction from the original starting point.
 P: 130 for the same question, to get the avg. velocity during the time what should i do? i know it is not just to add the 2 velocities given and divide by 2
P: 213
 Quote by the_d for the same question, to get the avg. velocity during the time what should i do? i know it is not just to add the 2 velocities given and divide by 2
Average velocity is total distance divided by total time.
Sci Advisor
HW Helper
P: 11,833
 Quote by christinono Aren't the words "distance travelled" and "displacement" different. I though displacement meant distance and direction from the original starting point.
 Quote by christinono Average velocity is total distance divided by total time.
I think that u've given yourself the answer. Besides,since in the problem we're not given the directions (so that we would think it as a vector projection problem),it's natural to assume the simpler version,which is what the teacher would want,right...?

Daniel.
 P: 130 A 500-kilogram sports car accelerates uni- formly from rest, reaching a speed of 30 me- ters per second in 6 seconds. During the 6 seconds, the car has traveled a distance of how many meters?? i got 180m is that correct? i used : distance = avg. velocity * change in time = (30m.s) * 6 = 180m
P: 213
 Quote by dextercioby I think that u've given yourself the answer. Besides,since in the problem we're not given the directions (so that we would think it as a vector projection problem),it's natural to assume the simpler version,which is what the teacher would want,right...? Daniel.
ha ha, very funny
Sci Advisor
HW Helper
P: 11,833
 Quote by the_d A 500-kilogram sports car accelerates uni- formly from rest, reaching a speed of 30 me- ters per second in 6 seconds. During the 6 seconds, the car has traveled a distance of how many meters?? i got 180m is that correct?
Check your numbers again...

Daniel.
P: 213
 Quote by the_d A 500-kilogram sports car accelerates uni- formly from rest, reaching a speed of 30 me- ters per second in 6 seconds. During the 6 seconds, the car has traveled a distance of how many meters?? i got 180m is that correct? i used : distance = avg. velocity * change in time = (30m.s) * 6 = 180m
Careful... 30m/s is not the average velocity, but rather the final velocity. Remember, average velocity is total displacement divided by the total time, or in this case (if a is constant),
$$\frac{V_i + V_f}{2} = \frac{0+30m/s}{2}$$
P: 130
 Quote by christinono Careful... 30m/s is not the average velocity, but rather the final velocity. Remember, average velocity is total displacement divided by the total time, or in this case (if a is constant), $$\frac{V_i + V_f}{2} = \frac{0+30m/s}{2}$$

where did u get the 2 from???
P: 213
 Quote by the_d where did u get the 2 from???
Isn't the average the sum of the 2 velocities divided by 2? In this case, the displacement would be: $$d = V_{ave}t$$
 Sci Advisor HW Helper P: 11,833 Kay,guys,let's leave side talks and refer to the initial problem ... Daniel.

 Related Discussions Differential Equations 3 Precalculus Mathematics Homework 5 General Math 3 Differential Equations 1 Set Theory, Logic, Probability, Statistics 1