Does Copper Nitrate React with Water?

  • Thread starter Thread starter ktpr2
  • Start date Start date
  • Tags Tags
    Copper Water
Click For Summary

Discussion Overview

The discussion revolves around the reaction of Copper(I) Nitrate with water, specifically whether it yields Copper(II) Nitrate and how the resulting compounds are structured. Participants explore the chemical balance of the reaction and the nature of the resulting complex.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • Some participants question whether Copper(I) Nitrate reacts with water to form Copper(II) Nitrate and how the charges balance in the reaction.
  • There is a suggestion that the product could be a Copper(II) hexaquo complex, represented as Cu(H2O)6^2+.
  • One participant expresses confusion about the presence of Copper(I) in the problem and whether a redox reaction is involved.
  • Another participant emphasizes that Copper(I) must be balanced with the negative charge of the nitrate ion, leading to a discussion about the necessity of Copper(II) for charge neutrality.
  • There are multiple references to the balancing of the chemical equation, with some participants attempting to clarify the stoichiometry involved.
  • One participant expresses uncertainty about the type of bonds formed in the compounds and admits to a lack of knowledge on the subject.

Areas of Agreement / Disagreement

Participants do not reach a consensus on whether Copper(I) or Copper(II) is the correct species involved in the reaction, and there are competing views on the nature of the resulting products and their bonding characteristics.

Contextual Notes

There are unresolved questions regarding the charge balance and the specific nature of the chemical bonds in the resulting compounds. The discussion reflects varying levels of understanding and assumptions about the chemistry involved.

ktpr2
Messages
189
Reaction score
0
Does Copper(I) Nitrate plus water { Cu(NO)3)2 (aq) + H20 } yeild Cu(NO3)2 3H20? (unbalanced)

From what I've been told, it could equal Cu(H2O)6^+2(aq) but I don't see the NO3 anywhere.
 
Chemistry news on Phys.org
ktpr2 said:
Does Copper(I) Nitrate plus water { Cu(NO)3)2 (aq) + H20 } yeild Cu(NO3)2 3H20? (unbalanced)

Do you see anything devious in the underlined part...?

ktpr2 said:
From what I've been told, it could equal Cu(H2O)6^+2(aq) but I don't see the NO3 anywhere.

What is that...??

Daniel.
 
Devious? Uh, Copper(I) has a positive charge, the anion NO3 has a negative charge; so it really must be Copper(II), to balance the molecule. Okay. Now you add water, h2o so all these elements have to show up on the product side. Since Cu(NO3)2 is balanced I have to ask myself if 3H2O is balanced. H is +, so 6+ goes with O which is 2-, 6-. So it looks pretty balanced.

I'll read ahead here. Water is is an extremely weak electrolyte. And ions dissolve in water well so it looks possible. What am I missing here?
 
ktpr2 said:
Devious? Uh, Copper(I) has a positive charge, the anion NO3 has a negative charge; so it really must be Copper(II), to balance the molecule. Okay.

How would the chemical bonds be realized in
[tex]Cu_{2}(NO_{3})_{2}[/tex]

compared to the regular
[tex]CuNO_{3}[/tex]

??


Daniel.
 
Metal+nonmetal = ion; must be charge neutral

[tex]Cu_{2}(NO_{3})_{2}; (NO_{3})_{2}[/tex] has charge of -1, so that's -2 overall, and since we have two atoms of Cu, it must be normal copper with a charge of -1.

I'm not sure "how the bond would be realized"; by charge forces :)?
 
BETWEEN WHOM??[itex]CuNO_{3}[/itex] is ELECTRICALLY NEUTRAL... :wink:

Daniel.
 
I guess it would have be a molecular bond of some kind. I profess ignorance as I'm just reading ahead for class.
 
I strongly doubt it.I would advise you to use the Cu(I) nitrate,viz.[itex]CuNO_{3}[/itex] :smile:

Daniel.
 
okay wait I don't have a choice of what kind of copper nitrate I can use. [tex]Cu(NO_3)_2_(aq_) + H_2O[/tex] is all i get. I just wanted to know what kind of product it would make. Thanks for your elucidation though
 
  • #10
Well [itex]Cu(NO_{3})_{2} \ _{aq.}[/itex] would mean Cu (II),right...?And why would the problem speak about Cu(I)??Is there some redox that i cannot/don't see? :confused:

Daniel.
 
  • #11
The complex you get is the copper (II) hexaquo complex.

[tex]Cu(NO_3)_2 + 6H_2O \longrightarrow Cu(H_2O)_6^{2+} + 2NO_3^-[/tex]
 
  • #12
Thanks,Gokul.I knew a clear mind would settle it. :wink:

So it was Copper (II) all the time... :rolleyes:

Daniel.
 

Similar threads

Replies
2
Views
5K
  • · Replies 7 ·
Replies
7
Views
3K
Replies
10
Views
4K
Replies
5
Views
3K
  • · Replies 3 ·
Replies
3
Views
4K
  • · Replies 1 ·
Replies
1
Views
10K
Replies
0
Views
2K
  • · Replies 7 ·
Replies
7
Views
7K
  • · Replies 6 ·
Replies
6
Views
4K
  • · Replies 2 ·
Replies
2
Views
3K