Calculating Potential at a Point Due to Multiple Point Charges

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SUMMARY

The discussion focuses on calculating the electric potential at a point due to three point charges positioned at the corners of a square with side length L. The user initially struggles with the concept but ultimately decides to apply the formula V = kQ/L for each charge and sum the potentials to find the total potential at point A. The final expression derived is ((1/square root 2) + 1) x kQ/L, which aligns with the textbook answer of square root 2 x k x Q/2L (square root 2 + 1). The user clarifies that "taking V = 0 at a great distance" indicates that the potential is negative at infinity.

PREREQUISITES
  • Understanding of electric potential and point charges
  • Familiarity with the formula V = kQ/r
  • Basic knowledge of vector addition in physics
  • Concept of electric potential being zero at infinity
NEXT STEPS
  • Study the principles of superposition in electric fields
  • Learn about the derivation of electric potential from point charges
  • Explore the implications of electric potential at infinity
  • Investigate the use of vector calculus in electrostatics
USEFUL FOR

Students of physics, particularly those studying electromagnetism, educators teaching electric potential concepts, and anyone seeking to deepen their understanding of electrostatic interactions among multiple point charges.

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Three point charges are arranged at the corners of a square of side L. What is the potential at the fourth corner (point A), taking V = 0 at a great distance?

OK, I am very confused. First of all, Giancoli (my textbook) seems to explain how to do this for one point charge, but I am confused about doing this for three charges. Second, what do they mean by "at a great distance"? I am assuming I would want to use V = 1/4piE0 Q/r. So I am guessing that I would have to do some kind of vector deal? Help appreciated. :redface:
 
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Um never mind. So I thought about this again and decided to use V=kQ/L for each point individually -- does that make sense? And then add them up to get V total. So I wound up with ((1/square root 2) +1) x kQ/L. My book says the answer is square root 2 x k x Q/2L (square root 2 + 1). I believe this is the same thing?
 
That "taking V = 0 at a great distance" means that an infinity the potential is 0,which means that the potential is actually negative.So you'd have to add 3 negative #-s,that's all.

Daniel.
 

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