Calculating Inverse Functions for Cubic Equations for TI-83 Users

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Discussion Overview

The discussion centers on calculating the inverse functions of the cubic equation x^3 + 4x + 1, specifically addressing methods for doing so and the use of a TI-83 graphing calculator. The scope includes theoretical understanding and practical application using technology.

Discussion Character

  • Exploratory, Technical explanation, Debate/contested, Homework-related

Main Points Raised

  • One participant requests an explanation for calculating the inverse function of the cubic equation and its implementation on a TI-83 calculator.
  • Another participant asserts that calculating the inverse requires the cubic formula, which is complex, and suggests that there may be alternative methods to solve the problem without explicitly finding the inverse.
  • A third participant insists that calculating the inverse is expected and asks for assistance if someone knows how to solve it.
  • A later reply acknowledges the existence of the cubic formula and inquires about the specific text of the problem to provide further help.

Areas of Agreement / Disagreement

Participants express differing views on the necessity and feasibility of calculating the inverse function explicitly, with some suggesting it may not be required while others maintain it is expected.

Contextual Notes

The discussion does not resolve the complexity of the cubic formula or the specific expectations of the problem, leaving open questions about the assumptions and requirements for calculating the inverse.

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Could somebody please explain to me how you would calulate the inverse functions of x^3+4x+1. And if possible how you would calulate that on the TI-83 graphing calculator. Thanks
 
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Could somebody please explain to me how you would calulate the inverse functions of x^3+4x+1.

You don't.

The exact formula for the inverse of this function requries the cubic formula, which is fairly complicated (although in this case the result is readable), and is almost certainly not what you are expected to do in class; there's probably a way to find the answer to your problem without having to explicitly compute this inverse.
 
It is expected. If you know how to solve this equation please tell me.
 
I see you've found the cubic formula. :smile: Do you still need help with it?

I'm curious what the actual text of the problem is.
 

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