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The current in an inductor when energy is stored. Please help 
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#1
Nov2512, 04:11 PM

P: 15

1. The problem statement, all variables and given/known data
What's the current in a 15mH inductor when the stored energy is 42μJ 2. Relevant equations E = 1/2 L i^2 3. The attempt at a solution .000042J = (.5)(.015H)(i^2) .000042J = (.0075)(i^2) .0056 = i^2 √ (.0056) = i .0748331 = i I need to put the answer in with only two sig figs so i put in .07 but it was wrong What am I doing wrong? 


#2
Nov2512, 05:16 PM

Sci Advisor
HW Helper
Thanks
P: 26,157



#3
Nov2512, 05:37 PM

P: 15

I'm dumb haha. Thanks!



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