The current in an inductor when energy is stored. Please help!!!

BryceHarper

1. The problem statement, all variables and given/known data

What's the current in a 15mH inductor when the stored energy is 42μJ

2. Relevant equations

E = 1/2 L i^2

3. The attempt at a solution

.000042J = (.5)(.015H)(i^2)
.000042J = (.0075)(i^2)
.0056 = i^2
√ (.0056) = i
.0748331 = i

I need to put the answer in with only two sig figs so i put in .07 but it was wrong
What am I doing wrong?

tiny-tim

Hi BryceHarper!
.07 is two decimal places but only one significant figure

BryceHarper

I'm dumb haha. Thanks!