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s0ft
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In the above figure, what would be the time period of the body(in red) under gravity, neglecting any non-conservative forces?
And what do call this type of situation? A gravity well or sth?
Okay, I think we can work something out here. Hope you're familiar with calculusJust take some variables and show me the way it's done.
I'll just add that the origin is located at the red dot at the bottom of the valley, and x & y refer to points along the white curve.Sdtootle said:X and y would be your normal Cartesian coordinates which are not in your picture, but need to be.
Yes.Your description of L is correct.
The time period of an oscillating body refers to the amount of time it takes for the body to complete one full cycle of motion. This can be measured in seconds, minutes, or any other unit of time.
The time period of an oscillating body can be calculated by dividing the total time it takes for the body to complete one full cycle by the number of cycles. For example, if a pendulum takes 2 seconds to complete one cycle and the experiment is repeated 5 times, the time period would be 2 seconds divided by 5, giving a time period of 0.4 seconds.
The time period of an oscillating body can be affected by several factors, including the length of the pendulum, the mass of the object, and the force of gravity. The type of material the pendulum is made of and the angle of release can also impact the time period.
The time period and frequency of an oscillating body are inversely related. This means that as the time period increases, the frequency decreases and vice versa. The frequency is calculated by dividing the number of cycles by the time period, or by using the equation frequency = 1/time period.
Yes, the time period of an oscillating body can be changed by altering the factors that affect it, such as the length of the pendulum or the mass of the object. It can also be changed by changing the force acting on the body, such as increasing or decreasing the amplitude of the oscillation.