Register to reply

Uniform Electric Fields

by datsqnp
Tags: electric, fields, uniform
Share this thread:
Jan14-13, 10:30 AM
P: 1
Coulomb's Law
F = kqq/r^2

Why does the intensity of a uniform electric field not get weaker in the middle? I would understand this if the intensity over distance was a linear function, but it isn't. The force near one of the plates would approach infinity, because r^2 is so small... but in the middle of the field even the forces of each side added up would not approach infinity, which means the field is not uniform. How are uniform electric fields possible?
Attached Thumbnails
Phys.Org News Partner Physics news on
Engineers develop new sensor to detect tiny individual nanoparticles
Tiny particles have big potential in debate over nuclear proliferation
Ray tracing and beyond
Jan14-13, 10:43 AM
Sci Advisor
PF Gold
ZapperZ's Avatar
P: 29,238
This is a very confusing post.

The expression for the Coulomb's law that you wrote is for a point or spherical charge distribution. Yet, you are talking about "plates" here.

For an infinite planar charge distribution, use Gauss's law and figure out the expression for the E-field. It is NOT the same as what you have written.

Jan14-13, 11:07 AM
jtbell's Avatar
P: 11,783
Or, you can find the electric field produced by a uniform plane sheet of charge by treating it as a collection of point charges and integrating over the whole sheet. If the sheet is large enough to be effectively "infinite" in size, you get the result that the field is uniform on either side of the sheet, in opposite directions on the two sides. (Using Gauss's Law is much quicker, if you know it and understand it.)

Register to reply

Related Discussions
Electric Fields Question- Uniform Field Advanced Physics Homework 5
Uniform Electric Fields Introductory Physics Homework 1
Uniform Electric Fields Introductory Physics Homework 3
Uniform/nonuniform electric fields Introductory Physics Homework 1
Electric charge and fields: uniform electric field Introductory Physics Homework 1