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E=hc/lambda... C |
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| Feb5-13, 04:25 PM | #1 |
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E=hc/lambda... C
I was thinking about refraction and phase velocity change, when i thought about whether the c in e=hc/lambda is always 3x10^8 or does it refer to the speed in the medium?
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| Feb5-13, 06:00 PM | #2 |
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Recognitions:
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in ##E=hc/\lambda## ##c## is always the speed of light in vacuum.
if the speed in the medium is important, it will show up in equations as a refractive index. as far as the photon is concerned, the "medium" is an array of atoms with empty space in between. |
| Feb6-13, 01:24 AM | #3 |
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So if wavelength decreases in a refractive medium, does that mean energy increases???
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| Feb6-13, 04:30 AM | #4 |
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Recognitions:
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E=hc/lambda... C
No. The relationship in question is the QM one for individual photons.
The EM wave description carries energy differently. http://farside.ph.utexas.edu/teachin...s/node119.html ... it's a different model. |
| Feb6-13, 07:46 AM | #5 |
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Anyway, you should have the formula getting back to E=hf which is valid in vacuum and media as well. |
| Feb6-13, 04:46 PM | #6 |
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Cheers folks. I now see that the qm and wave models must be evaluated differently and that E=hf is a more useful formula to employ :).
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