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Strength and Direction of Electric Field 
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#1
Feb513, 06:44 PM

P: 21

1. The problem statement, all variables and given/known data
What are the strength and direction of the electric field at the position indicated by the dot in the figure? Answer in component form. 2. Relevant equations E=kQ/r^2 3. The attempt at a solution E(+5) = (8.99E9)(5E9)/(0.02^2) = (1.1E5i, 0j) E(5) = (8.99E9)(5E9)/(0.02^2) = (0i, 2.8E4j) r(+10) = SQR(0.02^2+0.04^2) = 0.0447 E(+10) = (8.99E9)(10E9)/(0.0447^2) = 4.5E4 arctan(2/4)=26.57DEGE(+5) + E(5) + E(10) = (1.3E5i, 1.2E4j) Mastering Physics is telling me that this answer is wrong and I want to know where I screwed up. 


#2
Feb513, 07:12 PM

HW Helper
Thanks
PF Gold
P: 4,887

Your work looks good to me. I don't see any mistake.



#3
Feb513, 08:26 PM

Emeritus
Sci Advisor
HW Helper
PF Gold
P: 7,819

Keep at least two extra digits for all intermediate results. Roundoff your final result to the correct sig. dig. if whoever/whatever is grading your work is anal about such things. 


#4
Feb613, 08:04 PM

P: 21

Strength and Direction of Electric Field
Turns out it was the comma in my vector notation. Once I removed the comma, the computer accepted it. Looks like I'm a bit rusty on that stuff. Thank you both for your help.



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