Solution to Fourier Transform of f(θ) = |sin(θ)|

Click For Summary

Homework Help Overview

The discussion revolves around finding the Fourier transform of the function f(θ) = |sin(θ)|, with participants exploring various methods and approaches to tackle the problem.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the potential need for complex analysis versus integration by parts, with some expressing frustration over the latter's complexity. Questions arise regarding the applicability of standard integration techniques and the role of trigonometric identities in simplifying the problem.

Discussion Status

There is an ongoing exploration of different methods, including the use of trigonometric identities and integration techniques. Some participants suggest alternative approaches, but no consensus has been reached on a specific method to solve the problem.

Contextual Notes

Participants note the challenge of integrating functions with different parameters and the potential limitations of their current knowledge regarding Fourier transforms and trigonometric identities.

Stu165
Messages
10
Reaction score
0
I need to show the solution to the Fourier transfor of f(theta) = |sin(theta)|.

However i think that solving this needs to be done by complex anaylsis as integration by parts just keeps going on and on.
Does anyone know where to go with this?
 
Physics news on Phys.org
However i think that solving this needs to be done by complex anaylsis as integration by parts just keeps going on and on.

Does it provide an equation you can solve? Integrating [itex]\int e^x \sin x \, dx[/itex] is a standard IBP problem -- I bet it's in your calc 2 text. :smile:
 
I need to find

1/pi int sin(theta)cos(mk theta) d theta from 0 - pi

pi being the period

excuse the type I don't know how to do the equation thing.

I only find the cosine part of the transform cause it's and even function, therefore I don't integrate any sine components at the start. If that makes sense.
 
Sorry, I'm used to the exponential version. :smile:

All of your problems are solved with a simple trigonometric identity -- you can change a product of sine and cosine into a sum of two sines. I don't remember the exact form, but you can derive it yourself. Hint: consider sin(A+B) + sin(A-B).

(But, as you guessed, you could also do this by replacing cos x with Re[e^(ix)])
 
[tex]sin(2x) = 2 sinx cosx[/tex] but in this case sin and cosin have different parameters. I don't know how you'll go about that.
 
Hint: consider sin(A+B) + sin(A-B)

:-p
 
forgot to look at trig identities yet. I'll try that
 

Similar threads

  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
1
Views
3K
Replies
5
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K