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Binary Sequence |
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| Apr4-05, 06:41 PM | #1 |
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Binary Sequence
Not sure if this has been done... I sort of discovered this sequence myself, but who knows...
01000101010001000100010101000101... What comes next? |
| Apr4-05, 06:58 PM | #2 |
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I hope this isn't a joke.Anyone could take a # as 197847389748838393384848484949393822636464785885984 and pass it into base 2
Daniel. On normal basis,it should be "01" |
| Apr4-05, 07:31 PM | #3 |
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I don't know, but here's my answer: Since every 1 is followed by a 0 in the pattern so far, I'm going to guess that the next item in the sequence is a 0
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| Apr4-05, 07:48 PM | #4 |
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Binary Sequence
You're both correct as to the terms, but have not found out the pattern...
I'll post some more terms, though. 0100010101000100010001010100010101000101010001000100010101000100 That should be a big help. P.S. This is in no way a joke. (And it has only to do with "binary" in the sense of needing two symbols) EDIT: This includes the original terms. EDIT 2: It seems to be showing a space in the terms... there shouldn't be one... |
| Apr4-05, 07:58 PM | #5 |
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Is that really 00 at the end and not 01?
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| Apr4-05, 08:02 PM | #6 |
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| Apr4-05, 08:27 PM | #7 |
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Well, if you chop off the last 0 it's a palindrome.
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| Apr4-05, 08:44 PM | #8 |
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Here's a hint: Consider the number of terms I revealed the first post and the second post.[In White]
And Bicycle Tree: I totally didn't even notice that. Cool. |
| Apr4-05, 08:57 PM | #9 |
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The last 0 should totally be a 1.
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| Apr4-05, 09:03 PM | #10 |
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That and my previous one should probably be enough, but I can keep trying. Tell me if you really want the answer. |
| Apr4-05, 09:15 PM | #11 |
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I don't know, what's the answer? There are some repetitive patterns and they all predict a final 1.
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| Apr4-05, 09:21 PM | #12 |
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EDIT: Answer removed in order to give other people a chance. Hints still apply.
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| Apr4-05, 09:27 PM | #13 |
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That's pretty good.
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| Apr4-05, 09:34 PM | #14 |
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Thanks. Glad it was challenging.
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| Apr4-05, 10:00 PM | #15 |
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How about this sequence, then?
01101001100101101001011001101001... |
| Apr4-05, 10:13 PM | #16 |
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Answer:Associate the block 0110 with 0 and 1001 with 1. The sequence starts with 0110 and the n'th block of 4 thereafter is determined by the n'th entry in the pattern. For example, the fourth block of 4 is determined by the 4th entry, namely 0, so it is 0110.
That one was much easier, took only a minute or two. |
| Apr4-05, 10:21 PM | #17 |
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Well, I don't know why that one was so easy and the other one wasn't because I just tried the same idea on the first one and got this: 01 associates with 0, 00 associates with 1, start with 01 and proceed as in the post above, and that generates the original pattern you posted.
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