Speed of light measured the same by all inertial observers?

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Discussion Overview

The discussion revolves around the question of whether the speed of light is measured the same by all inertial observers, with a focus on the implications of non-inertial observers and the conditions under which light's speed remains constant. The scope includes theoretical reasoning and conceptual clarifications related to special relativity.

Discussion Character

  • Exploratory
  • Technical explanation
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • Some participants assert that the speed of light is universally c (3*10^8 m/s) for all observers, regardless of their state of motion.
  • One participant questions the validity of reasoning that a non-inertial observer, who is accelerating, can measure the speed of light as c at all times, suggesting that instantaneous speed does not equate to consistent measurements across different frames.
  • Another participant proposes that for a non-inertial observer accelerating at a constant rate, the speed of light is c only at the origin of their frame, with variations in clock rates affecting measurements elsewhere in the frame.
  • Repeated references to the speed of light being 299,792,458 m/s highlight the importance of precision in measurements.

Areas of Agreement / Disagreement

Participants express differing views on the implications of non-inertial frames and the constancy of the speed of light, indicating that the discussion remains unresolved with multiple competing perspectives.

Contextual Notes

Limitations include the dependence on specific conditions of acceleration and the potential for varying clock rates in non-inertial frames, which may affect the interpretation of light's speed.

metrictensor
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What is the speed of light measured the same by all inertial observers?
 
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[tex]3*10^8 \frac{m}{s}[/tex]
or
186,262 miles per second

A Google search would have found this faster.


(Or did you mean to ask why??)
 
Is this reasoning correct : suppose we have a non-inertial observer (towards another one)...then considering the local (in time) observer fitted at every time to the non-inertial one...then the speed of light is c for it, so it has to be c for the non-inertial observer at any time...so the speed of light is c for any observer ?
 
That sounds like it's awfully close to Zeno! If I understand what you are saying: "A non-inertial observer is accelerating but at each instant he is going at exactly the same speed as some inertial observer. For that inertial observer, the speed of light is c, therefore for the non-inertial observer, the speed of light is always c also!"

I'm not at all sure that is valid. The fact that, at each instant, the non-inertial observer is going at some speed doesn't mean that he observes what an inertial at the same speed would observe.
 
kleinwolf said:
Is this reasoning correct : suppose we have a non-inertial observer (towards another one)...then considering the local (in time) observer fitted at every time to the non-inertial one...then the speed of light is c for it, so it has to be c for the non-inertial observer at any time...so the speed of light is c for any observer ?

No, beacsue the coordinates tha he measures the speed of light to be c at any instant, whilst being stationary to him at thta isnatnt change from instant to instant as they arel accelarting relative to our non-inertial obsrebre at thta instant.
 
kleinwolf said:
Is this reasoning correct : suppose we have a non-inertial observer (towards another one)...then considering the local (in time) observer fitted at every time to the non-inertial one...then the speed of light is c for it, so it has to be c for the non-inertial observer at any time...so the speed of light is c for any observer ?

This is true for the specific case of an observer accelerating in a constant direction at a constant rate (a constant proper acceleration), with some important limitations.

The main limitation is that the speed of light in such an accelerating frame is equal to 'c' only at the origin of the frame. "Above" and "below" the origin of the frame clocks appear to run at different rates- one can use the usual formula for gravitational time dilation to calculate the apparent rates at which clocks run, one can also derive the same result from the Lorentz transform without using the gratatioanl time dilation formulas.
 
DaveC426913 said:
[tex]3*10^8 \frac{m}{s}[/tex]
or
186,262 miles per second

A Google search would have found this faster.


(Or did you mean to ask why??)

A Google search would have found

[tex]c= 299,792,458 \ \frac{\mbox{m}}{\mbox{s}}[/tex]

:wink:

Daniel.
 

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