Work problem, deals with great pyramid

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SUMMARY

The discussion focuses on calculating the volume of the Great Pyramid of Cheops, which stands 410 feet tall and has a base area of 755 feet square, using calculus. The volume is determined by integrating the volume of each slab from 0 to 410 feet. Additionally, the work done against gravity in constructing the pyramid involves calculating the weight of each differential mass element, factoring in the stone's density of 200 lb/ft³, and applying the formula for work done, mgh.

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stangeroo
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this is a calc problem, but I thought it fits better here than in the math section since its homework.

Here it goes:

the great pyramid of cheops is 410 feet tall and 755 feet square at the base. find the volume of the pyramid using calculus.

Part two:
The stone used in constructing it has a density of 200lb/ft^3. Find the work against gravity in building the pyramid.

I understand you integrate from 0 to 410 of the volume of each slab with a thickness of deltaX(or would it be delta y?) I am unsure how to calculate part two though, i haven't had much experience with work and force. anyone want to drop a hint or two :smile:
 
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You're right on the first part, and it doesn't matter what you call the integration variable. For the second part, the work done raising a mass m by a height h against a gravitational acceleration g is mgh. Add up the work done on each differential mass element ρdV, where ρ is the density.
 
For each horizontal slice, its area, its volume, and its weight can all be expressed as functions of y (distance from the x-axis). And for each slice, the work done is equal to the weight times the height.
 

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