For what values of x is │x^2-4│ not differentiable?

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The function │x^2-4│ is not differentiable at x = -2 and x = 2. This conclusion is reached by analyzing the limits of the derivative from both sides at these points. The definition of the derivative, which involves limits, reveals that the left-hand limit and right-hand limit differ at these critical points, confirming non-differentiability.

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For what values of x is │x^2-4│ not differentiable?
Is there a way to solve it without looking at the graph?
 
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Yep. Differentiate it and see where the derivative doesn't exist.
 
You have to use the definition of the derivative (the limit).

Notice how limit from the right and limit from the left are different as x approaches -2 and +2 from both sides.
 

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