Calculating Work Done in Thermodynamic Problem Q

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The discussion centers on calculating work done in a thermodynamic process involving nitrogen gas in a rigid tank. The initial conditions are 500 kPa and 300 K, with a final pressure of 800 kPa after heat transfer. It is established that in a rigid tank, the volume remains constant, leading to no work being done during the process. Instead, the changes in the state of the nitrogen are solely due to heat transfer, not work.

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Q. A 2-m3 rigid tank contains nitrogen gas at 500kPa and 300 K. Now heat is transferred to the nitrogen in the tank and the pressure of nitrogen rises to 800 kPa. The work done during this process is ...


Do we need to use

W = P2v2 - P1v1/ ( 1-n)

Some guidance requested please.

Thanks,
 
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Key words:
"rigid tank" meaning no change in volume. (I'm assuming this says a 2 cubic meter rigid tank.)
"heat transfered" meaning changes in state of the nitrogen are due to heat transfer, not work.

There is no work done, there is only heat transfer changing the state of the nitrogen.
 

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