Got a question with substitution?

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Homework Help Overview

The problem involves finding the maximum value of the expression 4x - 2xy + 3y under the constraint 4x - y = 2, suggesting a context in optimization and possibly calculus.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • The original poster attempts to use substitution to express y in terms of x and substitute it into the original equation. Some participants suggest differentiating to find critical points, while others question the appropriateness of this method for the problem at hand.

Discussion Status

Participants are exploring different methods to approach the problem, including substitution and differentiation. There is a suggestion to complete the square after expanding the expression, while another participant advocates for the use of Lagrange multipliers, indicating a divergence in methods being considered.

Contextual Notes

There appears to be uncertainty regarding the mathematical background required for some suggested methods, as well as the nature of the problem itself, whether it is purely algebraic or involves calculus.

MRAI
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Using the Substitution method, find the maximum value of

4x-2xy+3y subject to the constraint 4x-y=2

I can do the 1st part:

4x-y=2--->
4x-2=y

substitute this into the original equation:
4x-2x(4x-2)+3(4x-2)

Hope that right so far! but don't know where to go from there? anyone could help please?

thanks ;)
 
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then you differentiate wrt x and equal to zero to find max/min
 
what do u mean by wrt?
 
"wrt" : "with respect to"
CartoonKid was assuming this was a calculus problem. The standard method for solving "maximum- minimum" problems in calculus is to differentiate and set the derivative equal to 0. But since you apparently weren't aware of that, I suspect this is not a calculus problem!

If you multiply y= 4x-2x(4x-2)+3(4x-2) out, you get a quadratic. If you are doing problems like this, I presume you know how to complete the square to find the vertex of the graph which, in this problem, gives you the maximum value.

So: multiply this out, then complete the square.
 
This method is totally counterproductive...The method discovered by Lagrange is much more elegant...

Daniel.
 
But one would need a rather intermediate mathematical background to use them...
 

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