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Vector problems |
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| Apr25-05, 12:21 AM | #1 |
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Vector problems
Please help.
Given the 3 vectors a = -21 + 3j - k, b = 41 - j + 2k and c = -3i + 2j - 3k: 1. Find the unit vector perpendicular to a and b + c. 2. Evaluate a . b x c I'm completely clueless on how to approach the first question. Any help would be great. I'm not sure which product I'm meant to perform first in the second question. Also, 3. p1 and p2 are planes with cartesian equations 2x - y + 3z = 5 and x - 3y + z = -2, respectively, and l is the line of intersection of p1 and p2. Find a vector v parallel to l. I've already determined the normals of both planes: for p1 : 2i - j + 3k and for p2 : i - 3j + k, but I'm not sure where to go from here. Clearly v will be perpendicular to both normals, but I don't know how to find that vector. Any help for these questions would be greatly appreciated. |
| Apr25-05, 01:30 AM | #2 |
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Recognitions:
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Several questions by several posters, so let me just get you started on the first one. I assume you can add b + c. A vector perpendicular to a and b + c is the cross product of a with the sum of b + c. The unit vector is found by dividing that vector by its length.
In the second question, it only makes sense if you do the cross product first. If you did a . b there would be no vector to cross with c |
| Apr25-05, 01:42 AM | #3 |
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Thanks.
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| Apr25-05, 01:46 AM | #4 |
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Recognitions:
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Vector problems |
| Apr25-05, 01:48 AM | #5 |
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If you have time, could you tell me how you know that the cross product of b and c is perpendicular to both a and b + c? Thank you.
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| Apr25-05, 01:50 AM | #6 |
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| Apr25-05, 01:55 AM | #7 |
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Recognitions:
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The vector that is perpendicular to a and b + c is the cross product of the vector a with the vector that is the sum of the two vectors b + c. |
| Apr25-05, 01:59 AM | #8 |
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So a X (b + c)?
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| Apr25-05, 02:01 AM | #9 |
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Recognitions:
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| Apr25-05, 02:10 AM | #10 |
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Yep. Thanks for that.
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